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avanturin [10]
3 years ago
6

I need help!!!!! Solve for n 6n=72

Mathematics
2 answers:
scoundrel [369]3 years ago
8 0

Answer:

n = 12

Step-by-step explanation:

n = 72÷ 6

n = 12

thats the answer

tia_tia [17]3 years ago
7 0

Answer:

6n=72

n=72/6

n=12

.....................

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Which inequality describes the graph below?
Ainat [17]

Answer:

X>_1 and x<_7

Step-by-step explanation:

3 0
3 years ago
I would really appreciate help
alexira [117]
Check your y-intercept on the graph, it is at 3. Now go up two units and then move three units to the right you will see that it lands on a point. This is called rise/run. The shading goes above the line so that means you will use this symbol: >. Also it is a dotted line. So your inequality would be:
y > 2/3x + 3
I hope this helps love! :)
5 0
4 years ago
An elementary school is in a growing suburb. The school’s principal estimates that the current enrollment of 750 students will i
HACTEHA [7]

Answer:

62.9% in ten years

Step-by-step explanation:

This type of growth corresponds to what is called an exponential growth, since in the expression for the number of students keep including the multiplication of the same factor as the years go by, Let's start by analyzing what happens the first year:

The initial enrollment of 750 is expected to grow by 5%, therefore after one year the enrollment should be:

After one year = Year_1 = 750 + 5% increase = 750+750*0.05=750(1+0.05)

where we have used the decimal form of 5% as he factor 0.05 multiplying 750 (the initial enrollment) to give the increase.

After the second year, we consider a starting value of Year_1 enrollments that will increase another 5%, which gives: Year_2 = Year_1 + Year_1 * 0.05= Year_1 (1 + 0.05).

So replacing Year_1 by its original expression (750(1+0.05)) we notice that Year_2 = 750 * (1+0.05) * (1+0.05) = 750 * (1+0.05)^2

We can go on with this same reasoning and find that each year includes a new factor (1+0.05) to the new increasing enrollment.

At the end of 10 years, the number of enrollment will be:

750*(1+0.05)^10=1221.67

which we can round to 1222 students enrolled

This means and increase of: \frac{1222-750}{750} =0.62933

That is approximately 62.9%

6 0
3 years ago
19.2 is what percent of 24
Aleonysh [2.5K]
19.2 is 80% of 24. :)  :) :) 
6 0
4 years ago
A radio station plays yesterday by the beatles once every 2 days. Another station plays the same song once every 3 days. How man
mel-nik [20]

Both radio stations will play the same song on the same day <u>5 times</u> in 30 days.

<u><em>Explanation</em></u>

A radio station plays yesterday by the Beatles once every 2 days. Another station plays the same song once every 3 days.

For finding the day on which both radio stations will play the same song, we will just <u>find the LCM(Least Common Multiplier) of 2 and 3</u>. So, the LCM will be 6.

That means, <u>on every 6th day, both radio stations will play the same song</u>.

So, the number of times that both radio stations will play the same song on the same day in 30 days =(\frac{30}{6})= 5

8 0
4 years ago
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