Water can freeze at 32 degrees f
Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:
(-15,-10).
<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>
It is given by the derivative at x = x0, that is:
.
In this problem, the function is:

Hence the derivative is:

For a slope of -1, we have that:
0.4x + 5 = -1
0.4x = -6
x = -15.
For a slope of 1, we have that:
0.4x + 5 = 1.
0.4x = -4
x = -10
Hence the interval is:
(-15,-10).
More can be learned about derivatives and tangent lines at brainly.com/question/8174665
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Answer:
brainliest plz
Step-by-step explanation:
Answer:
The answer is 15
Step-by-step explanation:
hope this helps
Step-by-step explanation:
equation.
2(m+10)=4(m−15)
(2)(m)+(2)(10)=(4)(m)+(4)(−15)(Distribute)
2m+20=4m+−60
2m+20=4m−60
Step 2: Subtract 4m from both sides.
2m+20−4m=4m−60−4m
−2m+20=−60
Step 3: Subtract 20 from both sides.
−2m+20−20=−60−20
−2m=−80
Step 4: Divide both sides by -2.
−2m−/2=−80/−2
m=40