Answer = a) add them
When you multiply terms you add the exponents
For this case we have the following expression:
-2x ^ 2 (x + 5) + x (2x ^ 2-10x) + x
Rewriting we have:
-2x ^ 3 - 10x ^ 2 + 2x ^ 3 - 10x ^ 2 + x
Grouping terms with the same exponent:
x ^ 3 (-2 + 2) + x ^ 2 (-10 - 10) + x
-20x ^ 2 + x
Rewriting:
x (-20x + 1)
Answer:
The simple form of the expression is:
x (-20x + 1)
Answer:
x=0, -5/3
Step-by-step explanation:
I believe there are 3 short haired kittens, but let me know if I am wrong.
F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
