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Vikentia [17]
2 years ago
14

I need these from least to greatest A.11^4/11^11 B.1/11^-4 C.(11^-3)^-3 D.11^5•11^2

Mathematics
2 answers:
Sliva [168]2 years ago
6 0

Answer:

\frac{ {11}^{4} }{ {11}^{11} } < \frac{1}{ {11}^{ - 4} }   < {11}^{5} . {11}^{2}  <  ( {11}^{ - 3} )^{ - 3}

Step-by-step explanation:

A) \frac{ {11}^{4} }{ {11}^{11} }  =  {11}^{4 - 11}  =  {11}^{ - 7}  \\  \\  B)\frac{1}{ {11}^{ - 4} }  =  {11}^{4}  \\  \\C) ( {11}^{ - 3} )^{ - 3} =  {11}^{ - 3( - 3)}  =  {11}^{9}   \\  \\  D){11}^{5} . {11}^{2}   =  {11}^{5 + 2}  =  {11}^{7}  \\  \\  \because \:  {11}^{ - 7}  <  {11}^{4}  <  {11}^{7}  <  {11}^{9}  \\  \\  \therefore \: \frac{ {11}^{4} }{ {11}^{11} } < \frac{1}{ {11}^{ - 4} }   < {11}^{5} . {11}^{2}  <  ( {11}^{ - 3} )^{ - 3}

Sonbull [250]2 years ago
3 0

Answer:

A.11^4/11^11

Step-by-step explanation:

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