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Alex17521 [72]
3 years ago
11

Can u guys PLEASE answer the depreciation question ASAP. THIS IS URGENT!

Mathematics
2 answers:
Furkat [3]3 years ago
8 0

Answer: the value of the car after 7 years is $11220

Step-by-step explanation:

The formula for determining depreciation is expressed as

A = P(1 - r)^t

Where

A represents the final value of the car after t years.

P represents the present value of the car.

r represents the rate of depreciation

t represents the number of years.

From the information given

P = 35000

r = 15% = 15/100 = 0.15

t = 7 years

Therefore,

A = 35000(1 - 0.15)^7

A = 35000(0.85)^7

A = 11220.198

Rounding up yo the nearest dollar, it becomes $11220

kifflom [539]3 years ago
6 0

Answer:

34

Step-by-step explanation:

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Finger [1]

s =   \frac{1}{g {t}^{2}\pi }

multiply through by

g {t}^{2} \pi

s \times g {t}^{2} \pi =  \frac{1}{g {t}^{2} \pi}  \times g {t}^{2} \pi

sg {t}^{2} \pi = 1

dividing through by

sgπ

{t}^{2}  =  \frac{1}{sg\pi}

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4 0
3 years ago
Read 2 more answers
If there are 18 marbles in a jar and Edgar's absolute guessing error is what was Edgar's original guess?
Anon25 [30]

Answer:

wait what was edgar's absolute guessing error

Step-by-step explanation:

greater than 18, or less than 18

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3 years ago
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Help I will be marking brainliest!!!
expeople1 [14]

Answer:

A. 51°

Step-by-step explanation:

By the theorem of intersecting secants.

m\angle B=\frac{1}{2} (m\widehat{LW} - m\widehat{MU})

44.5\degree =\frac{1}{2} (140\degree - m\widehat{MU})

2\times 44.5\degree = 140\degree - m\widehat{MU}

89\degree = 140\degree - m\widehat{MU}

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3 years ago
Miss lawrence buys 8 ounces of smoked salmon at 17.98 per pound how much money does mis lawrence spend on smoked salmon
elena-14-01-66 [18.8K]
Do cross multiplication.
Convert ounce to pound.
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3 years ago
Write an equation of the line that passes through the point (5, -8) with slope 5
Oxana [17]

\Large\texttt{Answer}

equation=\bold{y=5x-33}

\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}

\Large\texttt{Process}

<em>⇨ Use the formula below</em>

<em />\bf{y-\hfill\stackrel{y \:co-ordinate}{y1}=\hfill\stackrel{slope}{m}(x-\hfill\stackrel{x\:co-ordinate}{x1)}}

<em>⇨ Substitute the parameters:</em>

<em />

<em />\bold{y-(-8)=5(x-5)}

\bold{y+8=5x-25}

\bold{y=5x-33}

Hope that helped

4 0
2 years ago
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