I believe the answer is c
First, let's find the time where the ship arrives to point C
t=d/V, t= 45/30=1.5h
if the ship's departure time is at 1.5h, on the point C, let 's find its arrival to the point O, V=D/Dt, Dt=tfinal-tinitial
Dt=D/V= 20/30=0.6h=t final -t initial, implies t final=0.6+t initial=0.6+1.5=2.1h
so the ship will be on the radar at 2.1h,
Answer:
the answer would be 5b as the exterior angle is subdivided with the co efficient
Step-by-step explanation:
215 DOLLARS
271/5 = 54.2 hours
How: 2/5 +2/5+3/5 times 5 (bc its 3 different dogs with different times for 5 days) +3 (for 3 dogs) times 4/5 (bc each dog take 4/5 of an hour each) + 1/5 (for the extra 1/5 of an hour pepper wanted to stay outside)
*Important: in the parentheses are the explanation of why I did each addition or multiplication
Answer:
x = 5
Step-by-step explanation:
x + 5 = 10
<u> -5 -5</u>
x = 5
<em><u>Hope this helped! Have a nice day! Plz mark as brainliest!!!</u></em>
<em><u>-XxDeathshotxX</u></em>
