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Sveta_85 [38]
3 years ago
8

Which system of equations is represented by the matrix below?

Mathematics
2 answers:
Anestetic [448]3 years ago
8 0

Answer:

c.

Step-by-step explanation:

h

Charra [1.4K]3 years ago
6 0

Answer:

  C

Step-by-step explanation:

The elements of the matrix need to match the coefficients in the equations.

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Denise Rose the number cube that has sides labeled 1 to 6 and then flips a coin what is the probability that she rolls in odd nu
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4 0
2 years ago
Line with a slope 6 passes through the points (2,-10) and (5,g)
Irina-Kira [14]

Answer:

8 =g

Step-by-step explanation:

We have two points so we can use the slope formula

m = ( y2 -y1)/(x2-x1)

6 = ( g - -10)/(5-2)

6 = (g+10)/(5-2)

6 = (g+10)/3

Multiply each side by 3

6*3 = g+10

18 = g+10

Subtract 10

18-10 =g

8 =g

4 0
3 years ago
A boat on a river travels downstream between two points, 90 mi apart, in 1 h. The return trip against the current takes 2 1 2 h.
docker41 [41]

Answer:

A)63miles per hour.

B)27 miles per hour

Step-by-step explanation:

HERE IS THE COMPLETE QUESTION

boat on a river travels downstream between two points, 90 mi apart, in 1 h. The return trip against the current takes 2 1 2 h. What is the boat's speed (in still water)??b) How fast does the current in the river flow?

Let the speed of boat in still water = V(boat)

speed of current=V(current)

To calculate speed of boat downstream, we add speed of boat in still water and speed of current. This can be expressed as

[V(boat) +V(current)]

It was stated that it takes 1hour for the

boat to travels between two points of 90 mi apart downstream.

To calculate speed of boat against current, we will substact speed of current from speed of boat in still water. This can be expressed as

[V(boat) - V(current)]

and it was stated that it takes 2 1/2 for return trip against the Current

But we know but Speed= distance/time

Then if we input the stated values we have

V(boat) + V(current)]= 90/1 ---------eqn(1)

V(boat) - V(current) = 90/2.5----------eqn(2)

Adding the equations we have

V(boat) + V(current) + [V(boat) - V(current)]= 90/2.5 + 90/1

V(boat) + V(current) + V(boat) - V(current)]=90+36

2V(boat)= 126

V(boat)=63miles per hour.

Hence, Therefore, the speed of boat in still water is 63 miles per hour.

?b) How fast does the current in the river flow?

the speed of the current in the river, we can be calculated if we input V(boat)=63miles per hour. Into eqn(1)

V(boat) + V(current)]= 90/1

63+V(current)=90

V(current)= 27 miles per hour

Hence,Therefore, the speed of current is 27 miles per hour.

7 0
3 years ago
C=-7/15 and x=2/5 c-4x write your answer in simplest form
pogonyaev

9514 1404 393

Answer:

  -31/15

Step-by-step explanation:

Put the numbers in the expression and do the arithmetic.

  c-4x=-\dfrac{7}{15}-4\cdot\dfrac{2}{5}=-\left(\dfrac{7}{15}+\dfrac{8}{5}\right)\\\\=-\left(\dfrac{7}{15}+\dfrac{24}{15}\right)=\boxed{-\dfrac{31}{15}}

__

Your graphing calculator can probably help with this.

5 0
3 years ago
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