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3 years ago

Given: All snarfs are yelbs. All yelbs are blue.

Mathematics

2 answers:

yulyashka [42]3 years ago

6 0

Answer:

The answer is: C. Some slokes are yelbs.

Step-by-step explanation:

Since all snarfs are yelbs. And some slokes are snarfs. Some slokes are yelbs, because all the yelbs are snarfs.

The answer is: C. Some slokes are yelbs.

scZoUnD [109]3 years ago

4 0

Answer:

C. Some slokes are yelbs.

Step-by-step explanation:

Given that ;

All snarfs are Yelbs

All Yelbs are Blue

Migs are Green or Pink

Some Slokes are Snarfs

We can see that some Slokes are related to snarfs hence connected to Yelbs

It will be correct to say that some slokes are yelbs

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3 years ago

One third of a number and 3,increased by 1 is 24

tangare [24]

Answer:

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Step-by-step explanation:

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3 years ago

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snow_lady [41]

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Answer:

H the range is all real numbers

Step-by-step explanation:

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3 years ago

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dexar [7]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5? Quadratic formula: x = StartFracti

weqwewe [10]

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

$x=\frac{-2-\sqrt{19}}{3}$ and $x=\frac{-2+\sqrt{19}}{3}$

Step-by-step explanation:

The quadratic formula of the quadratic equation ax² + bx + c = 0, is

$x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}$

To find the solution of the quadratic equation by using quadratic formula

Find the values of a, b, and c from the quadratic equation
Substitute these values in the quadratic formula
Calculate the values of x

∵ -3x² - 4x + 5 = 0

∴ a = -3 , b = -4 and c = 5

- Substitute these values in the quadratic formula

∵ $x=\frac{-(-4)+\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}$

∴ $x=\frac{4+\sqrt{16+60}}{-6}$

∴ $x=\frac{4+2\sqrt{19}}{-6}$

- Simplify by dividing up and down by -2

∴ $x=\frac{-2-\sqrt{19}}{3}$

∵ $x=\frac{-(-4)-\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}$

∴ $x=\frac{4-\sqrt{16+60}}{-6}$

∴ $x=\frac{4-2\sqrt{19}}{-6}$

- Simplify by dividing up and down by -2

∴ $x=\frac{-2+\sqrt{19}}{3}$

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

$x=\frac{-2-\sqrt{19}}{3}$ and $x=\frac{-2+\sqrt{19}}{3}$

Learn more:

You can learn more about quadratic equation in brainly.com/question/7361044

#LearnwithBrainly

9 0

3 years ago

Read 2 more answers