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3 years ago

Solve the system of equations using the substitution method.y=2,2x+y=8

Mathematics

2 answers:

den301095 [7]3 years ago

7 0

Answer:

x=3, y=2

Step-by-step explanation:

y=2

substitute 2 for y

2x+2=8

x=3

OlgaM077 [116]3 years ago

3 0

Answer:

x=3

Step-by-step explanation:

2x+2=8

2x=6

x=3

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What is the end behavior of the function?

Vinil7 [7]

Answer:

X->-infinite, graph is positive +(infinite)

X-> + infinite, graph is negative (-infinite)

Step-by-step explanation:

When you study end behaviour of a polynomial, you verify it's highest exponent. If it is odd, like this exercise, it's Y values come from negative infinity to positive infinity. If the coefficient is negative, it is the opposite, it comes from positive infinite to negative infinite.

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3 years ago

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What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16

kicyunya [14]

Answer:

$y=\pm i \sqrt{7}$

Step-by-step explanation:

Given equation is $\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

Factor denominators then solve by making denominators equal

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$y\left(y+4\right)-4\left(y-4\right)=9$

$y^2+4y-4y+16=9$

$y^2=9-16$

$y^2=-7$

take squar root of both sides

$y=\pm \sqrt{-7}$

$y=\pm i \sqrt{7}$

Hence final answer is $y=\pm i \sqrt{7}$ .

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3 years ago

Ineed help help me please

melamori03 [73]

The symbol ₁₂P₉ represents the permutations of 9 quantities out of 12.
By definition,
$_{12}P_{9} = \frac{12!}{(12-9)!} = \frac{12!}{3!}$

From the calculator,
12! = 479,001,600
3! = 6

Therefore
₁₂P₉ = 479001600/6 = 79,833,600

Answer: 79,833,600

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