from the provided focus point and directrix, we can see that the focus point is above the directrix, meaning is a vertical parabola and is opening upwards, thus the squared variable will be the "x".
keeping in mind the vertex is half-way between these two fellows, Check the picture below.
![\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvertical%20parabola%20vertex%20form%20with%20focus%20point%20distance%7D%20%5C%5C%5C%5C%204p%28y-%20k%29%3D%28x-%20h%29%5E2%20%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7Bvertex%7D%7B%28h%2Ck%29%7D%5Cqquad%20%5Cstackrel%7Bfocus~point%7D%7B%28h%2Ck%2Bp%29%7D%5Cqquad%20%5Cstackrel%7Bdirectrix%7D%7By%3Dk-p%7D%5C%5C%5C%5C%20p%3D%5Ctextit%7Bdistance%20from%20vertex%20to%20%7D%5C%5C%20%5Cqquad%20%5Ctextit%7B%20focus%20or%20directrix%7D%5C%5C%5C%5C%20%5Cstackrel%7B%22p%22~is~negative%7D%7Bop%20ens~%5Ccap%7D%5Cqquad%20%5Cstackrel%7B%22p%22~is~positive%7D%7Bop%20ens~%5Ccup%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

Yes. It is a vertical shift up by 4 units.
A vertical shift will be up or down along the y-axis.
Answer:
Step-by-step explanation:
You need to know:
Vertex form = 
The vertex is at
(h, k)
<u>Need to know about perfect squares </u>
<u>Need to know how to complete the square.</u>
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<u>To convert
you need to complete the square on the equation.</u>
Complete the Square
Divide -2 by 2 and then square it.


Add the one to the parentheses and subtract the one from the 5
Square
Now we have
<u>Next add</u> -5 - 1 = -6
Our quadratic is in vertex form now.
Vertex form = 
our equation =
Vertex = (1, -6)
Answer:
y = -1/6x +2
Step-by-step explanation:
The black vertical line in the middle of the graph is the y-axis. The blue line crosses it a the point marked 2. This is known as the y-intercept.
The slope of the line is the ratio of "rise" (vertical change) to "run" (horizontal change).
There is a marked point on the line at the y-intercept, where x=0 and y=2. There is another marked point to the right of that, where x=6 and y=1.
The vertical change between those two points is 1 -2 = -1.
The horizontal change between those two points is 6 -0 = 6
The slope is then -1/6.
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The slope-intercept form of the equation of a line is often written as ...
y = mx + b
where "m" is the slope (-1/6), and "b" is the y-intercept.
Using the values we found above, the equation of the line is ...
y = -1/6x +2