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kompoz [17]
3 years ago
10

What is the solution for the equation?

Mathematics
1 answer:
Ugo [173]3 years ago
7 0
Cross multiply
5(b3-2) = 2(3b2 - 2b2 -5)
5b3 - 10 = 6b3 - 4b2 - 10
5b3 = 6b3 - 4b2
0 = b3 - 4b2
0 = b2(b - 4)

b2 = 0 —> b = 0
b-4=0 —> b = 4
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