What is the solution for the equation?

Mathematics

1 answer:

Ugo [173]3 years ago

7 0

Cross multiply
5(b3-2) = 2(3b2 - 2b2 -5)
5b3 - 10 = 6b3 - 4b2 - 10
5b3 = 6b3 - 4b2
0 = b3 - 4b2
0 = b2(b - 4)

b2 = 0 —> b = 0
b-4=0 —> b = 4

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