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ankoles [38]
3 years ago
13

Is the sequence arithmetic or geometric? {3, 9, 27...}

Mathematics
2 answers:
frutty [35]3 years ago
7 0

3×3=9

9×3=27

it would be geometric bc you times it by 3

Nesterboy [21]3 years ago
3 0

Answer:

This is geometric

Step-by-step explanation:

r=3

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Leonard earns $8.75 per hour working at a bowling alley. Last weekend, he worked for 5.4 hours. How much money did Leonard earn
sertanlavr [38]

Answer:

$47.25

Step-by-step explanation:

Earnings = (rate of pay)(number of hours worked)

Here,

Earnings last weekend = ($8.75/hr)(5.4 hrs) = $47.25

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Find the median of the set of data.
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Find the accumulated value after 12 years of deposits of $360 made at the beginning of every 3 months and earning interest of 7.
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Write an inequality to represent the graph. у -5 3 2- x -5 4 3 2 0 2 5 6 8 -2 -3 -5 (3,5) -6- (0,7) -8 -9 -10
Anastaziya [24]

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Step-by-step explanation:

5 0
3 years ago
Evaluate exactly without the use of a calculator (remember to rationalize any denominators). a.(cos 60o)(sin 270o) + tan 225o b.
Rom4ik [11]

Given:

The trigonometric expressions are given as,

\begin{gathered} a)\text{ }(\cos 60\degree)(\sin 270\degree)+\tan 225\degree \\ b)-\tan 240\degree+(cos45\degree)(\sec 135\degree) \end{gathered}

Explanation:

a)

The given expression can be rewritten as,

=(\cos 60\degree)(\sin (360\degree-90\degree))+\tan (270\degree-45\degree)\text{ . . . .  .(1)}

Since, from the trigonometric ratios,

\begin{gathered} \sin (360\degree-90\degree)=-\sin 90\degree \\ \tan (270\degree-45\degree)=\cot 45\degree \end{gathered}

On plugging the obtained ratios in equation (1),

=(\cos 60\degree)(-\sin 90\degree)+\cot 45

Substitute the trigonometric values in the above equation.

\begin{gathered} =\frac{1}{2}(-1)+1 \\ =-\frac{1}{2}+1 \\ =\frac{1}{2} \end{gathered}

Hence, the exact value of the expression is 1/2.

b)

The given expression can be rewritten as,

=-\tan (270\degree-30\degree)+(\cos 45\degree)(\sec (90\degree+45\degree))\text{ . . . ..(2)}

Since, from the trigonometric ratios,

\begin{gathered} \tan (270\degree-30\degree)=\cot 30\degree \\ \sec (90\degree+45\degree)=-\csc 45\degree \end{gathered}

On plugging the obtained ratios in equation (2),

=-\cot 30\degree+(\cos 45\degree)(-\csc 45)

Substitute the trigonometric values in the above equation.

\begin{gathered} =-\sqrt[]{3}+\frac{1}{\sqrt[]{2}}(-\sqrt[]{2}) \\ =-\sqrt[]{3}-1 \end{gathered}

Hence, the exact value of the expression is -√3-1.

7 0
2 years ago
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