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alexandr402 [8]
3 years ago
13

60 miles on 2.5 gallons?

Mathematics
1 answer:
alexdok [17]3 years ago
7 0

60 miles /2.5 gallons  is 24 miles / gallon

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(9x^4-3x^3+4x^2+5x+7) + (11x^4-4x^2-11x-9)
icang [17]

Answer:

20x^4 - 3x^3 - 6x - 2

5 0
3 years ago
Which is the solution set of the inequality 15 y minus 9 less-than 36 y greater-than nine-fifths y less-than nine-fifths y less-
Vaselesa [24]

Answer:

C. y<3

Step-by-step explanation:

We are required to determine the solution set of the inequality

15y-9

Step 1: Add 9 to both sides

15y-9+9

Step 2: Divide both sides by 15

15y \div 15

The solution set of the given inequality is: y<3.

The correct option is C.

4 0
3 years ago
Read 2 more answers
A. Write the equation ax + b = c in terms of x.
Oksanka [162]

Answer:

x=c/a-b/a

Step-by-step explanation:

ax+b=c

1) Subtract b from both sides:

ax=c-b

2) Divide both sides by a:

x=c/a-b/a

5 0
3 years ago
Read 2 more answers
2. If 5 + x = 12, and you add-5 to the left side of equation, what should you add to the right side of the equation?
Dafna1 [17]

Answer:

b.-5

Step-by-step explanation:

Whatever you do to one side you do to the other

8 0
3 years ago
Read 2 more answers
You stand 100’ from the base of a tower. The tower is 1,058’ tall. What is the angle from where you are standing to the top of t
hodyreva [135]

Answer: 85°


Step-by-step explanation:

Trig functions are remembered by


SOD CAD TOA,


sin = opposite / distance, cos = adjacent / distance, and tan = opposite / adjacent.


Here we have the adjacent side = 100, opposite side = 1058. The tower would fall over if it weren't vertical, and we assume the area is flat and level. So tangent of the answer is 10.58.


We need the angle whose tangent is 10.58.

On Android calculator you swipe left to get the trig functions, tap INV, if RAD is showing tap it to change it to DEG, and tap tan⁻¹. Swipe right and you see tan⁻¹(. Enter 10.58 and the result shows 84.6005606. If it shows 1.47655833 tap the RAD in upper left to change to DEG.

8 0
3 years ago
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