The answer to this problem is Beryllium is an alkaline earth metal.
Filter flasks are
also known as vacuum, suction or the Buchner flasks. They have thick walls and also
have a short glass tube. The thick walls are designed to enable the filter withstand
high pressures of vacuum applied to filter substances. Generally this is used
for filtering.
While the Erlenmeyer flask
also called as a conical flask, is a titration flask which consists of a
conical body, a flat bottom, and round neck. This is used for used for general
uses such as mixing, titrations, preparation of cultures, for
recrystallization, and for supporting filter funnels.
<span>Lastly, the Volumetric flasks are graduated flasks which having markings
for different volumes. They are calibrated accurately for a specific amount of
liquid that can be contained in it hence this is specially used for storing
precise amounts of liquid. </span>
Answer:
2H+(aq) + 2OH-(aq) → 2H2O(l)
Explanation:
Step 1: The balanced equation
2HCl(aq)+Ca(OH)2(aq) → 2H2O(l)+CaCl2(aq)
This equation is balanced, we do not have the change any coefficients.
Step 2: The netionic equation
The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will.
2H+(aq) + 2Cl-(aq) + Ca^2+(aq) + 2OH-(aq) → 2H2O(l) + Ca^2+(aq) + 2Cl-(aq)
After canceling those spectator ions in both side, look like this:
2H+(aq) + 2OH-(aq) → 2H2O(l)
The empirical formula, <span>C<span>H2</span></span>, has a relative molecular mass of
<span>1×<span>(12.01)</span>+2×<span>(1.01)</span>=14.04</span>
This means that the empirical formula must be multiplied by a factor to bring up its molecular weight to 70. This factor can be calculated as the ratio of the relative masses of the molecular and empirical formulas
<span><span>7014.04</span>=4.98≈5</span>
Remember that subscripts in molecular formulas must be in whole numbers, hence the rounding-off. Finally, the molecular formula is
<span><span>C<span>1×5</span></span><span>H<span>2×5</span></span>=<span>C5</span><span>H<span>10</span></span></span>
