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aivan3 [116]
3 years ago
11

Balance this equation. If a coefficient of "1" is required, choose "blank" for that box. ____CO +____ O2 → ____CO2

Chemistry
2 answers:
lorasvet [3.4K]3 years ago
7 0
<h3 /><h3>Answer: </h3>

<u>2</u> CO2 +<u> 2 </u>O2 → <u>2</u> CO2

Black_prince [1.1K]3 years ago
4 0
<h3><u>Answer;</u></h3>

2, Blank, 2 ;

<h3><u>Explanation;</u></h3>

The balanced chemical equation would be;

2 CO + O2 → 2 CO2

Balancing a chemical equation ensures that the number of atoms of each element are equal on both the reactants side and the products side. This ensures that the law of conservation of mass is obeyed in chemical reactions.

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How many grams of carbon dioxide will form if 5.5 g of C3H8 burns in 15 g of O2?
mr Goodwill [35]
C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2
5 0
3 years ago
You have just isolated a new radioactive element. If you can determine its half-life, you will win the Nobel Prize in physics. Y
lbvjy [14]

Answer: 2.58 days

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = age of sample  = 6 days

a = initial amount of the reactant  =  1 g

a - x = amount left after decay process   = 0.2 g

a) to find the rate constant

6=\frac{2.303}{k}\log\frac{1.0}{0.2}

k=\frac{2.303}{6}\log\frac{1.0}{0.2}

k=0.268days^{-1}

b) for completion of half life:  

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

t_{\frac{1}{2}}=\frac{0.693}{0.268}=2.58days

The half life is 2.58 days

3 0
3 years ago
The equilibrium constant, Kc, for the following reaction is 3.61×10-4 at 426 K. PCl5(g) PCl3(g) + Cl2(g) When a sufficiently lar
iogann1982 [59]

Answer:

the concentration of PCl5 in the equilibrium mixture = 296.20M

Explanation:

The concept of equilibrium constant was applied where the equilibrium constant is the ration of the concentration of the product over the concentration of the reactants raised to the power of their coefficients. it can be in terms of concentration in M or in terms of Pressure in atm.

The detaied steps is as shown in the attached file.

8 0
3 years ago
Sodium chloride is an example of a
Andrei [34K]
C. Weak acid is the correct answer
6 0
3 years ago
Read 2 more answers
PLZ HELP!!!!!!!!!!!!!
gregori [183]

117.22 g are needed to react with an excess of Fe2O3 to produce 156.2 g of Fe.

Explanation:

                  Moles of Fe = Mass of Fe in grams / Atomic weight of Fe

                                        = 156.2 / 55.847

                  Moles of Fe  = 2.79.

The ratio between CO and Fe id 3 : 2.

                  Moles CO needed  = 2.79 * (3 / 2)

                                                   = 4.185.

 To calculate Atomic weight of CO,

                  Atomic weight of carbon = 12.011

                  Atomic weight of oxygen= 15.9994

        Atomic weight of CO = 12.011 + 15.9994 = 28.01 g / mol.

                 Mass of CO   = 4.185 * 28.01 = 117.22 g.      

5 0
3 years ago
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