1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
madreJ [45]
3 years ago
13

Help plz I’ll give brainliest

Mathematics
2 answers:
marusya05 [52]3 years ago
6 0

Answer:

7 movies watched the bill will be 53$.

Step-by-step explanation:

0  =>  25

1   =>  (+4) 29

2  =>  (+4) 33

3  =>  (+4) 37

4  =>  (+4) 41

5  =>  (+4) 45

6  =>  (+4) 49

7  =>  (+4) 53

starting with the basic fee, which is 25$, there is an increment of 4$ for each movie that will be watched. So for 7 movies, the cost will be 53$.

Bumek [7]3 years ago
4 0

Answer:

it will be 49 because u will add four because 37+4=41 41+4=45. 45+4= 49

You might be interested in
What is the slope of the line represented by the equation y = 4/5 x -3? A-1 B-4/5 C4/5 D3
Cerrena [4.2K]

Option C

<u>ANSWER: </u>

For the given equation slope is \frac{4}{5} so the correct option is c.

<u>SOLUTION: </u>

Given, line equation is $y=\frac{4}{5} x-3$

We need to find the slope of the given equation.

Above given equation is in the form of slope intercept form, i.e. y = mx + c

Where m is the slope and c is the intercept made on axis by this line.

By comparing the given equation and the general form, we can conclude that,  m = \frac{4}{5} and c = -3

hence, for the given equation slope is \frac{4}{5}. so the correct option is c.

8 0
3 years ago
Read 2 more answers
What is the answer to ax-8b=c
HACTEHA [7]
Donut star bucks and donald duck
8 0
3 years ago
Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
1 year ago
Using the figure below, find the lengyh of x.<br><br>​
katrin [286]

Answer:

what i don't understand why you are not answer that question

5 0
3 years ago
What is the product of and (6+5i) and (3-7i) ?<br><br> -17-27i<br> -17+27i<br> 53+27i<br> 53-27i
USPshnik [31]
We are going to make the product step by step.
 We have:
 (6 + 5i) * (3-7i)
 Multiplying:
 ((6) * (3)) + ((6) * (- 7i)) + ((5i) * (3)) + ((5i) * (- 7i))
 Rewriting:
 18 - 42i + 15i - 35i ^ 2
 18 - 42i + 15i - 35 * (- 1)
 18 - 42i + 15i + 35
 53 - 27i
 Answer:
 
the product of and (6 + 5i) and (3-7i) is:
 
53-27i
5 0
3 years ago
Other questions:
  • Please explain me and tell me the right answer.
    5·1 answer
  • Write an equation of the line, in point-slope form, that passes through the two given points.
    13·2 answers
  • Write 52% as a decimal.
    12·2 answers
  • What are the 2 most common exponents you will deal with when finding roots?
    9·1 answer
  • Einsteinium-253253253 is an element that loses about \dfrac23
    14·2 answers
  • A number is divided by 3. Then 14 is added to the quotient. The result is 33. What is the orginal number?
    8·1 answer
  • When writing an expression or equation to represent a real-world situation, why is it important to be able to describe what each
    10·1 answer
  • If you cut a 35-inch long stick in the ratio 2:3, how long would each part be?
    6·1 answer
  • PAST DUE DATE PLEASE HELP. whats is the surface are of this figure​
    7·1 answer
  • Moe, Curly, and Larry are brothers. Moe is the youngest brother, white Larry is the oldest brother. Their ages are consecutive i
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!