we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=k or y=kx
so
we have
a) for x=1 y=0.50--------> y/x=0.50/1------> 0.50
b) for x=2 y=1--------> y/x=1/2-------> 0.50
c) for x=3 y=1.50--------> y/x=1.50/3-----> 0.50
d) for x=5 y=2.50--------> y/x=2.50/5----> 0.50
the value of k is equal to 0.50
so
<span>the relationship forms a direct variation. </span>
the equation is
y=0.50*x
Verify
for x=1
y=0.50*(1)------> y=0.50-----> is correct
for x=2
y=0.50*(2)------> y=1.00-----> is correct
for x=3
y=0.50*(3)------> y=1.50-----> is correct
for x=5
y=0.50*(5)------> y=2.50-----> is correct
Answer:
x=30
Step-by-step explanation:
Find the value of x that will make A and B parallel
For A & B to be parallel, the interior angles must be supplementary, i.e.
4x+2x = 180
6x=180
x=30
When x=30, the interior angles are 120 and 60 which are supplementary.
The two tangents are parallel to each other because the two lines perpendicular to the same line are parallel to each other.
Lk + JK = JL
The answer is Parallel to each other
Answer:
58 degreess
3x+11=4x-5
-3x -3x
11=x-5
+5 +5
16=x
x=6
3(6)+11
18+11
29
29*2
58
Step-by-step explanation:
Answer:
Explanation:
<u>1. Given vector:</u>
- length: 4.00 mm = magnitude of the vector
- angle: 23.5º north of east = 23.5º from the x-axys (counterclockwise)
<u>2. y-component</u>
The y-component may be determined using the sine ratio, the angle from the x-axys (counterclockwise direction), and the magnitude of the vector.
- sine (23.5º) = y-component / magnitude
- y-component = magnitude × sine (23.5º) = 4.00 mm × sine (23.5º) = 1.59 mm.
