Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Answer: 5 times x<-45 the solution is x<-9
Step-by-step explanation:
less than is < and greater than is >
Answer:
95? Sorry if I'm wrong.... :)
Step-by-step explanation:
Answer:
√9 × √6
√54
√27 × √2
Step-by-step explanation:
We can obtain the answer to the question given above as illustrated below:
3√6
Recall
a√b = √(a×a×b)
Thus,
3√6 = √(3×3×6)
3√6 = √(9 × 6)
Recall
√(a × b) = √a × √b
√(9 × 6) = √9 × √6
Therefore,
3√6 = √9 × √6
Recall
√9 × √6 = √(9 × 6)
√9 × √6 = √54
Thus,
3√6 = √54
Recall
√54 = √(27 × 2)
√54 = √27 × √2
Therefore,
3√6 = √27 × √2
Therefore,
3√6 = √9 × √6 = √54 = √27 × √2