Write the equation of the line that passes through the points (-3, -2) and (0, -3)
2 answers:
Answer:
Step-by-step explanation:
One of the given points is the y-intercept. That means you can write the equation in slope-intercept form once you have found the slope.
m = slope = (change in y)/(change in x) = (y2 -y1)/(x2 -x1)
= (-3 -(-2))/(0 -(-3)) = -1/3
The slope-intercept form for slope m and intercept b is ...
y = mx +b
For slope -1/3 and intercept -3, the equation is ...
y = -1/3x -3
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Answer:
<em>Observe attached image</em>
<em>Function zeros:</em>
(3, 0), (5, 0)
<em>Vertex:</em>
(4, 2)
<em>Axis of symmetry:</em>
<em></em>
Step-by-step explanation:
<u>First factorize the function</u>
<em>Take -2 as a common factor.</em>
<em>Now factor the expression </em>
You must find two numbers that when you add them, obtain the result -8 and multiplying those numbers results in 15.
These numbers are -5 and -3
Then we can factor the expression in the following way:
<em><u>The quadratic function cuts the x-axis at </u></em><em>x = 3 and at x = 5.</em>
Now we find the coordinates of the vertex.
For a function of the form the x coordinate of its vertex is:
In the function
<u>Then the vertice is:</u>
The y coordinate of the symmetry axis is
The axis of symmetry is a vertical line that cuts the parabola in two equal halves. This axis of symmetry always passes through the vertex.
<u>Then the axis of symmetry is the line</u>
<u>The solutions and the vertice written as ordered pairs are:</u>
<em>Function zeros:</em>
(3, 0), (5, 0)
<em>Vertex:</em>
(4, 2)
