Answer:
x = -2, y = -1, z = 4
Step-by-step explanation:
4x + 6y - z=-18
z = 18 + 4
x + 6
y
3x +2y - 4z = -24
z = 6 + (3x)/
4 + y
/2
- 5x + 3y + 2z = 15
z = 15/2 + (5x)/2 - (3y)/2
18 + 4
x + 6
y = 6 + (3x)/
4 + y
/2 = 15/2 + (5x)/2 - (3y)/2
x = -22y/13 - 48/13
4(-22y/13 - 48/13) + 6y - (15/2 + (5(-22y/13 - 48/13))/2 - (3y)/2) = -18
Compute the output value of the variables x and y with respect to the input values of x, y, and z coefficients.
An aritmetic sequence is like this

where a1=first term and d=common difference
geometric is

where a1=first term and r=common ratio
can it be both aritmetic and geometric
hmm, that means that the starting terms should be the same
therfor we need to solve

what values of d and r make all natural numbers of n true?
are there values that make all natural numbers for n true?
when n=1, then d(1-1)=0 and r^(1-1)=1, so already they are not equal
the answer is no, a sequence cannot be both aritmetic and geometric
Answer:
10s
100s
Step-by-step explanation:
One of the 6s are in the 10th digit position
the other one is in the 100th digit position
Answer:
r is 32
Step-by-step explanation:
because yes it was y
Answer: C, S, and X
Step-by-step explanation: These are the variables to your equation.