Ask question

Ask question

All categories

2 years ago

9

If the supplies on shelf A are normally $7 each and the supplies on shelf B are normally $6 each, how much will you save on each

package plan from part a? Buying the first package will save $ and buying the second package will save $

1 answer:

mrs_skeptik [129]2 years ago

3 0

Pretty sure you’ll save 1 dollar for b and and lose one dollar for a

You might be interested in

Although you love to watch TV, you have made a goal to spend more time outdoors. You decide that you will spend 2 times as many

ohaa [14]

2t=o

t=the hours of television
0=the hours outdoors

Since the #hours outdoors is twice the #hours of television, the equation is 2t=o

8 0

2 years ago

Read 2 more answers

I need help i dont understand this

mel-nik [20]

140 tickets sold at the door

Step by Step Explanation:

x = tickets sold in advance
y = tickets sold at the door

We use the formula ax+by=c and a+b=c

x + y = 514
17x + 20y = 9158

y = 514 - x
17x + 20(514 - x)
17x + 10,280 - 20x = 9,158
-3x + 10,280 = 9,158
-3x = -11222
x = 374

This is for tickets sold in advance so we need to find y

374 + y = 514
y = 140

140 tickets were sold at the door

8 0

2 years ago

Exponential function f is represented by the table. x -2 -1 0 1 2 f(x) -46 -22 -10 -4 -1 Function g is represented by the equati

Scrat [10]

The statement that describes better about function is "Both functions are increasing, but function g increases at a faster average rate." since option (c) is correct.

Given the table

x f(x)

-2 -46

-1 -22

0 -10

1 -4

2 -1

We have to choose which statement describes better about function

Let us assume $f(x)=ab^x+c$

at x=0, f(0)=-10

So, -10 =a+c

Similarly, by satisfying the above table in the f(x)

$f(x)=\frac{33}{5} (\frac{1}{11})^x-\frac{17}{5}$

$f'(x) > 0$

So we can say that f(x) is an increasing function.

$g(x) = - 18 (\frac{1}{3} )^ x + 2$

$g^ \prime (x) = - 18 (\frac{1}{3} )^ x ln(1/3)$

ln(1/3) < 0

So, g^ \prime (x) > 0

So, g(x) is an increasing function.

For any x∈f(x) and x∈g(x) $g'(x) > f'(x)$

So, g increases at a faster average rate

Thus, Both functions are increasing, but function g increases at a faster average rate.

Learn more about increasing functions here: brainly.com/question/12940982

#SPJ10

7 0

1 year ago

Find the value of 216m³ - 8n³ if 6m - 2n=0 and mn=12

mestny [16]

Answer:

0

Step-by-step explanation:

Given that,

6m - 2n=0

=>6m=2n

=>n=3m [divide both side by 2]

& mn=12

Now,

216c - 8n³

= 216m³- 8(3m)³

=216m³- 8 .27m³

=216m³- 216m³

=0

6 0

2 years ago

Class A has 15 pupils and class B has 29 pupils.

Vaselesa [24]

The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Class A has 15 pupils and class B has 29 pupils. The mean score for class A is 55. Hence:

Mean score of A = (sum of all scores) / 15

55 = (sum of all scores) / 15

sum of all scores in A = 825

The mean score for both classes is 76. Hence:

[(sum of all scores in A) + (sum of all scores in B)]/(total number of pupils) = mean score of both classes

[825 + (sum of all scores in B)]/(15 + 29) = 76

sum of all scores in B = 2519

Mean score of B = (2519) / 29 = 86.86

The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.

Find out more on equation at: brainly.com/question/13763238

#SPJ1

6 0

1 year ago