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3 years ago

The table below represents a linear function f(x) and the equation represents a function g(x):

Mathematics

1 answer:

forsale [732]3 years ago

6 0

Answer:

Step-by-step explanation:

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Anybody who could help me with this

VladimirAG [237]

For number 1, you subtract the error from the estimated mass ( 342-325 = 17)
Then divide the result by the estimated mass multiplied by 100 to find the percentage ( 17/325 *100 = 5.23)

The percent error is 5.23 %

5 0

3 years ago

Proving Pythagorean Theorem

MrRissso [65]

Answer:

Step-by-step explanation:

${a}^{2} + {b}^{2} = {c}^{2}$

ssubstitute a and b for any of the numbers (3 or 6) and get 36+9 which is 45

45 =

${c}^{2}$

so you would need to find the square root to get c

4 0

2 years ago

BRAINLIEST ASAP! PLEASE HELP ME :)

Margaret [11]

Answer:

$\large \boxed{\text{3.0 mi/h}}$

Step-by-step explanation:

Let x = the current of the river

Then 21 + x = the speed going downstream (with the current)

a nd 21 - x = the speed going upstream (against the current)

Distance = speed × time

d = st

t = d/s

Time going downstream = time going upstream

$\begin{array}{rcll}\dfrac{2.4}{21+ x}& = & \dfrac{1.8}{21 - x} &\\\\2.4& = &(21 + x) \dfrac{1.8}{21 - x} &\text{Multiplied each side by (21 + x)}\\\\2.4(21 - x)& = & 1.8(21 + x) &\text{Multiplied each side by (21 - x)}\\50.4 - 2.4x&=& 37.8 + 1.8x&\text{Removed parentheses}\\50.4 & = & 37.8 + 4.2x & \text{Added 2.4x to each side}\\\end{array}\\$

$\begin{array}{rcll}12.6 & = & 4.2x & \text{Subtracted 37.8 from each side}\\x & = &\dfrac{12.6}{4.2}&\text{Divided each side by 4.2}\\\\ & = &\mathbf{3.0}& \text{Simplified}\\\\\end{array}\\\text{The current is $\large \boxed{\textbf{3.0 mi/h}}$}$

Check:

$\begin{array}{rcl}\dfrac{2.4}{21+ 3}& = & \dfrac{1.8}{21 - 3}\\\\\dfrac{2.4}{24}& = & \dfrac{1.8}{18}\\\\0.10 & = & 0.10\\\end{array}$

4 0

3 years ago

At the start of a hike, a hiker was at an elevation of -50 feet (where 0 represents sea level). The hiker climbs at a rate of 15

OLga [1]

Answer:

15t - 50 > 5

Step-by-step explanation:

Initial point = -50 ft
Climbing rate = 15 ft / min
Time = t

<u>Required inequality:</u>

15t - 50 > 5

<u>Solution:</u>

15t > 55
t > 55/15
t > 3 10/15 = 3 40/60 min = 3 min 40 seconds

7 0

3 years ago

Read 2 more answers

Help me pls! Thank you so much

frosja888 [35]

$\bf cos\left[tan^{-1}\left(\frac{12}{5} \right)+ tan^{-1}\left(\frac{-8}{15} \right) \right]\\
\left. \qquad \qquad \quad \right.\uparrow \qquad \qquad \qquad \uparrow \\
\left. \qquad \qquad \quad \right.\alpha \qquad \qquad \qquad \beta
\\\\\\
\textit{that simply means }tan(\alpha)=\cfrac{12}{5}\qquad and\qquad tan(\beta)=\cfrac{-8}{5}
\\\\\\
\textit{so, we're really looking for }cos(\alpha+\beta)$

now.. hmmm -8/15 is rather ambiguous, since the negative sign is in front of the rational, and either 8 or 15 can be negative, now, we happen to choose the 8 to get the minus, but it could have been 8/-15

ok, well hmm so, the issue boils down to

$\bf tan(\theta)=\cfrac{opposite}{adjacent}\qquad thus
\\\\\\
tan(\alpha)=\cfrac{12}{5}\cfrac{\leftarrow opposite=b}{\leftarrow adjacent=a}
\\\\\\
\textit{so, what is the hypotenuse "c"?}\\
\textit{ well, let's use the pythagorean theorem}
\\\\\\
c=\sqrt{a^2+b^2}\implies c=\sqrt{25+144}\implies c=\sqrt{169}\implies \boxed{c=13}\\\\
-----------------------------\\\\
\textit{this simply means }\boxed{cos(\alpha)=\cfrac{5}{13}\qquad \qquad sin(\alpha)=\cfrac{12}{13}
}$

now, let's take a peek at the second angle, angle β

$\bf tan(\beta)=\cfrac{-8}{15}\cfrac{\leftarrow opposite=b}{\leftarrow adjacent=a}
\\\\\\
\textit{again, let's find "c", or the hypotenuse}
\\\\\\
c=\sqrt{15^2+(-8)^2}\implies c=\sqrt{289}\implies \boxed{c=17}\\\\
-----------------------------\\\\
thus\qquad \boxed{cos(\beta)=\cfrac{15}{17}\qquad \qquad sin(\beta)=\cfrac{-8}{17}}$

now, with that in mind, let's use the angle sum identity for cosine

$\bf cos({{ \alpha}} + {{ \beta}})= cos({{ \alpha}})cos({{ \beta}})- sin({{ \alpha}})sin({{ \beta}})\\\\
-----------------------------\\\\
cos({{ \alpha}} + {{ \beta}})= \left( \cfrac{5}{13} \right)\left( \cfrac{15}{17} \right)-\left( \cfrac{12}{13} \right)\left( \cfrac{-8}{17} \right)
\\\\\\
cos({{ \alpha}} + {{ \beta}})= \cfrac{75}{221}-\cfrac{-96}{221}\implies cos({{ \alpha}} + {{ \beta}})= \cfrac{75}{221}+\cfrac{96}{221}
\\\\\\
\boxed{cos({{ \alpha}} + {{ \beta}})=\cfrac{171}{221}}$

8 0

3 years ago