Answer:
this is assuming brown eyes are dominant
6a 9/16
b.3/16
c 3/16
d. 1/16
Explanation: there might be an easy way to calculate it but I draw it out and use the dominance and lettering and just count I used slide 5 as a starting point
to do more than this would require seeing the square on slide 1 they are referring to as it is specific to 2 parents
4. a Bb and bb
b. bb and bb
5. BBEE BBEe BbEEBbEe
BBEe BBee BbEe Bbee
BbEE BbEe bbEE bbEe
BbEe Bbee bbEe bbee
2 a Bb
b Brown hair
c. Bb and brown hair
d. blonde hair
e. BB
3. A50%
c. 50%
25%
75%
25%
Answer:
Transcription and RNA processing (splicing)
Explanation:
Although Howard is almost right, the DNA sequence does not precisely relate to the protein sequence. First of all, the DNA is transcribed to an primary mRNA molecule. Bur before the mRNA is ready to be translated into an amino acid sequence, it must be processed into a mature mRNA.
This includes adding a 3' poly A tail, and a 5' cap, and importantly for this question, splicing.
Splicing is the removal of non protein coding intermediate sequences called introns from the protein coding regions (exons) of a primary mRNA. This means that lots of the DNA sequence is not dictated by the final protein, as many of the intervening sequences have been removed by splicing.
The seven major plates<span> are the African </span>plate<span>, Antarctic </span>plate<span>, Eurasian </span>plate<span>, Indo-Australian </span>plate<span>, North American </span>plate<span>, Pacific </span>plate<span>and South American </span><span>plate</span>
Answer:
3' TACCGCAAA 5'
Explanation:
Transcription is the process by which a particular DNA sequence (e.g., a gene) is used as a template to synthesize a complementary RNA sequence that grows in a 5′ → 3′ direction. This RNA molecule is usually a messenger RNA (mRNA) which is then used to synthesize a polypeptide chain (i.e., a protein) by a process called translation. The complementary RNA molecule produced during transcription is synthesized according to the base pair rules, i.e., Adenine (A) bases always pair with Thymine (T) bases, while Guanine (G) bases always pairs with Cytosine (C) bases. In RNA, Uracil (U) bases pair with adenine, thereby replacing thymines during transcription.
That’s the only part I know (might not be right not to sure)
