Answer:
A coordinate system,or Coordinate plain ,is used to locate points in a 2-dimensional plane.
explanation:
A coordinate plain is formed by the intersection of two lines.One line is vertical and the other is horizontal.The vertical line is called y- axis and the horizontal line is called x-axis. It is two dimensional plane,which means it has length and breadth but no depth.The point where both the lines intersect is called the point of origin.Any point can be located on the coordinate plain by numbers(x,y). These pair of numbers are called coordinates.
It is used to plot points and lines.This system explains algebraic concepts .it has four equal divisions called quadrants namely I ,II,III,IV.
One way is to type it into your trusty TI and use the table from presing stat and then stat againg then calc then 4
so the equation that I got from your set of points is y=1.983333333333333x+0.80555555555
7 times 2=14
14 times 2=24
24 times 1=24
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
The general equation of a circle is given by:
(x-a)^2+(x-b)^2=r^2
where:
(a,b) is the center
r is the radius
given the equation:
x^2+y^2=36
it means that the equation is centered at (0,0) with radius of 6 units. Thus a translation of 5 units to the left and 4 units up, will change the new center to
(-5,4)
thus the equation will be:
(x+5)^2+(y-4)^2=36
Answer: (x+5)^2+(y-4)^2=36
