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Snezhnost [94]
3 years ago
15

Calculate the specific heat capacity of the unknown metal given the

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
3 0

Answer: The specific heat capacity of the unknown metal given is 0.466 J/g^{o}C.

Explanation:

Given: Mass = 225 g

Change in temperature = 13^{o}C

Heat energy = 1363 J

The formula used to calculate specific heat is as follows.

q = m \times C \times \Delta T

where,

q = heat energy

m = mass of substance

C = specific heat

\Delta T = change in temperature

Substitute the values into above formula as follows.

q = m \times C \times \Delta T\\1363 J = 225 g \times C \times 13^{o}C\\C = \frac{1363 J}{225 g \times 13^{o}C}\\= 0.466 J/g^{o}C

Thus, we can conclude that the specific heat capacity of the unknown metal given is 0.466 J/g^{o}C.

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Hydrocarbons that lack ____________ are called saturated hydrocarbons, or ___________.
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Hydrocarbons that lack π bond are called saturated hydrocarbons or alkanes

<h3>Hydrocarbons</h3>
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<h3>Alkanes</h3>
  • Alkanes also konwn as parafins
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Therefore, Hydrocarbons that lack π bond are called saturated hydrocarbons

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which of the following activities could cause liquid molecules to overcome intermolecular attractive forces and become gas molec
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The answer is C. increasing the temperature of the liquid.

Increasing the temperature of the liquid also means that you are providing energy to the liquid, which makes the molecules overcome intermolecular attractive forces, move more constantly, and become gas molecules.

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3 years ago
How many grams are needed to make 2 L of solution of 4 M LiNO3?
katen-ka-za [31]

Answer:

552 g of LiNO₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 2 L

Molarity of LiNO₃ = 4 M

Mass of LiNO₃ =?

Next, we shall determine the number of mole of LiNO₃ in the solution. This can be obtained as follow:

Volume of solution = 2 L

Molarity of LiNO₃ = 4 M

Mole of LiNO₃ =?

Molarity = mole /Volume

4 = mole of LiNO₃ / 2

Cross multiply

Mole of LiNO₃ = 4 × 2

Mole of LiNO₃ = 8 moles

Finally, we shall determine the mass of of LiNO₃ needed to prepare the solution. This is can be obtained as follow:

Mole of LiNO₃ = 8 moles

Molar mass of LiNO₃ = 7 + 14 + (16×3)

= 7 + 14 + 48

= 69 g/mol

Mass of LiNO₃ =?

Mole = mass /Molar mass

8 = Molar mass of LiNO₃ /69

Cross multiply

Molar mass of LiNO₃ = 8 × 69

Molar mass of LiNO₃ = 552 g

Thus, 552 g of LiNO₃ is needed to prepare the solution.

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Dennie wanted to see if crayfish preferred one kind of food over another. He gave one group of crayfish plants, both living and
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