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Lady_Fox [76]
3 years ago
13

(Chemistry) Match each item with the correct statement below.

Chemistry
1 answer:
Colt1911 [192]3 years ago
4 0

Number\;1:\;Formula.\\\\Number\;2:\;Solution\\\\Number\;3:\;Chemistry\\\\Number\;4:\;Solute\\\\Number\;5:\;Mass\\\\Number\;6:\;Matter\\\\Number\;7:\;Alloy\\\\Number\;8:\;Aqueous\\\\Number\;9:\;Quantitative

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A 155.0 g piece of copper at 128 oC is dropped into 250.0 g of water at 17.9 oC. (The specific heat of copper is 0.385 J/goC.) C
Mamont248 [21]

Answer:

T_{eq}=23.85^oC

Explanation:

Hello,

In this case, as the copper's heat loss is gained by the water, the following energetic relationship is:

\Delta H_{Cu}=-\Delta H_{H_2O}

Therefore the equilibrium temperature shows up as:

m_{Cu}Cp_{Cu}(T_{Cu}-T{eq}) = m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})\\\\T_{eq}=\frac{m_{Cu}Cp_{Cu}T_{Cu}-m_{H_2O}Cp_{H_2O}T_{H_2O}}{m_{Cu}Cp_{Cu}-m_{H_2O}Cp_{H_2O}} \\

Thus, by knowing that water's heat capacity is 4.18J/g°C, one obtains:

T_{eq}=\frac{155.0g*0.385\frac{J}{g^oC}*128^oC+250.0g*4.18\frac{J}{g^oC}*17.9^oC}{155.0g*0.385\frac{J}{g^oC}+250.0g*4.18\frac{J}{g^oC}}=23.85^oC

Best regards.

6 0
3 years ago
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Ok so the answer for this question, A student measured the mass of salt that can dissolve in 100 mL of water at five different t
Dmitriy789 [7]

Answer:

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Explanation:

8 0
3 years ago
Calculate the amount of heat required to melt 2108 g of water. The enthalpy of fusion of water is ΔHfus=6.010 kJ/mol.
vesna_86 [32]

since the unit for the heat of fusion is kJ/mol, you're going to have to convert the grams into moles in order to cancel out the unit. After that, you can solve like normal.

6 0
3 years ago
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chubhunter [2.5K]

Answer:

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Brønsted-Lowry Base : NH3, C3H7NH2, CH3)3N

Neither : NaBr, CCl4

Explanation:

8 0
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omeli [17]
You can start by recycling plastic and paper more often! Pick up trash that you see laying in the street and don’t add to it by littering!
7 0
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