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UNO [17]
3 years ago
11

How did newton use creativity and logic in his approach to investigating light

Chemistry
2 answers:
zhuklara [117]3 years ago
6 0

Answer:

Newton’s approach was creative because he thought of the new idea of passing a single color of light through a prism. His approach was also logical. He reasoned that comparing white light and a single color of light would allow him to compare the two hypotheses.

Explanation:

fiasKO [112]3 years ago
3 0
He used prisms to demonstrate how white light is in fact made
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In the Bronsted-Lowry model of acids and bases, an _____ is a hydrogen donor and a _____ is a hydrogen acceptor.
Natasha_Volkova [10]

Answer:

According to Bronsted-lowry concept  an acid is a hydrogen donnor and a base is a hydrogen acceptor.

Explanation:

4 0
3 years ago
Chemistry help!!
Scrat [10]

The student originally has 252 grams of water in this experiment.

LAW OF CONSERVATION OF MASS:

  • The law of conservation of mass explains that matter (mass) can neither be created nor destroyed but can be changed from one form to another.

  • This means that in a chemical reaction, the sum of the masses of the reactants must equate to the total mass of product(s).

  • According to this question, a student conducts an experiment to separate water into hydrogen and oxygen. The student collects 28.0 g of hydrogen and 224.0 g of oxygen.

  • Since hydrogen and oxygen are the constituent elements of water, the sum of their masses must equate the mass of water.

  • Therefore, 224g of oxygen + 28g of hydrogen = 252g of water.

Learn more at: brainly.com/question/24996173?referrer=searchResults

8 0
3 years ago
how many molecules of sulfuric acid are in a spherical raindrop of diameter 6.0 mm if the acid rain has a concentration of 4.4 *
Vitek1552 [10]

Answer:

The number of moles =

Moles=4.97\times 10^{-8}

The number of molecules =

Molecules = 2.99\times 10^{16}

Explanation:

Volume of the sphere is given by :

V=\frac{4}{3}\pi r^{3}

here, r = radius of the sphere

radius=\frac{diameter}{2}

radius=\frac{6.0}{2}

Radius = 3 mm

r = 3 mm

1 mm = 0.01 dm (1 millimeter = 0.001 decimeter)

3 mm = 3 x 0.01 dm = 0.03 dm

r = 0.03 dm

<em>("volume must be in dm^3 , this is the reason radius is changed into dm"</em>

<em>"this is done because 1 dm^3 = 1 liter and concentration is always measured in liters")</em>

V=\frac{4}{3}\pi 0.03^{3}

V=\frac{4}{3}\pi 2.7\times 10^{-5}

V=1.13\times 10^{-4}dm^{3}

V=1.13\times 10^{-4}L   (1 L = 1 dm3)

Now, concentration "C"=

C=4.4\times 10^{-4}moles/liter  

The concentration is given by the formula :

C=\frac{moles}{Volume(L)}

This is also written as,

Moles = C\times Volume

Moles=1.13\times 10^{-4}\times 4.4\times 10^{-4}

Moles=4.97\times 10^{-8}moles

One mole of the substance contain "Na"(= Avogadro number of molecules)

So, "n"  mole of substance contain =( n x Na )

N_{a}=6.022\times 10^{23}

Molecules =

Molecule=4.97\times 10^{-8}\times 6.022\times 10^{23}

Molecules = 2.99\times 10^{16} molecules

7 0
3 years ago
What is the mass of 2.16 moles of sulfur dioxide (SO2)?
Luda [366]
<h3>Answer:</h3>

138 g SO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 2.16 moles SO₂

[Solve] grams (mass) SO₂

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of S - 32.07 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of SO₂ - 32.07 + 2(16.00) = 64.07 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 2.16 \ mol \ SO_2(\frac{64.07 \ g \ SO_2}{1 \ mol \ SO_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 138.391 \ g \ SO_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

138.391 g SO₂ ≈ 138 g SO₂

6 0
3 years ago
Help :( i don’t understand
Natali [406]

Answer:

measuring cups, do you have them? look

4 0
3 years ago
Read 2 more answers
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