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3 years ago

Which number line shows the solution to 1/4 X + 1 < 5

Mathematics

1 answer:

alex41 [277]3 years ago

5 0

Answer:

I think it's the third one

Step-by-step explanation:

I've done this before, but try the 3rd one, if not then try the second one. it's been awhile since I've done this. I'm sorry if I'm wrong

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PLSS helpp <br><br> btw have a nice day

Natali5045456 [20]

It’s the first one! The table shows X going up and Y going down, so the slope would be negative!

8 0

3 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago

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pishuonlain [190]

-120 + 13m, at time m = 6, would be -120 + 78, or -42 feet.

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3 years ago

Each card in a set of cards has one of the letters from the word mathematics. The cards are shuffled. What is the probability of

maksim [4K]

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3 years ago

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Let g(x) be the reflection of f(x) = x 2 + 3 in the x-axis. What is the function rule for g(x)?

nevsk [136]

G(x) will be g(x)=-2x-3 because it is a reflection of f(x) over the x-axis. F(x)'s reflection over the x-axis will become -f(x).

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3 years ago

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