So Basically, these are similar. So that means that (2x/5.5)=(3x-3/7.5). Then when you cross multiply, you find that x=11. So that means BA/FE=22/5.5=4. You can verify by checking (3*11-3)/7.4=4. So now that you know the scale factor is 4, just do 4*8=32.
Taking the derivative of 7 times secant of x^3:
We take out 7 as a constant focus on secant (x^3)
To take the derivative, we use the chain rule, taking the derivative of the inside, bringing it out, and then the derivative of the original function. For example:
The derivative of x^3 is 3x^2, and the derivative of secant is tan(x) and sec(x).
Knowing this: secant (x^3) becomes tan(x^3) * sec(x^3) * 3x^2. We transform tan(x^3) into sin(x^3)/cos(x^3) since tan(x) = sin(x)/cos(x). Then secant(x^3) becomes 1/cos(x^3) since the secant is the reciprocal of the cosine.
We then multiply everything together to simplify:
sin(x^3) * 3x^2/ cos(x^3) * cos(x^3) becomes
3x^2 * sin(x^3)/(cos(x^3))^2
and multiplying the constant 7 from the beginning:
7 * 3x^2 = 21x^2, so...
our derivative is 21x^2 * sin(x^3)/(cos(x^3))^2
Answer:
x = 5/7 -> 0.714285 which to the nearest tenth would be 0.7
Step-by-step explanation:
is it x*2 or x^2?
If it were x to the power of two, then the answer would be about x1 = 0.594875 and x2 = 8.40512
Step-by-step explanation:
4x² - 12x + 9 = 5 → 4x² - 12x + 4 = 0 → x² - 3x + 1 = 0
∆ = b² - 4ac → ∆ = (-3)² -4(1)(1) = 9 - 4 = 5
x = (-(-3) ± √5)/2(1) = (3 ± √5)/2
x² - 3x + 1 = 0 → (x - 3/2)² - 9/4 + 1 = 0 → (x - 3/2)² = 5/4 → x - 3/2 = ±√5 / 2 → x = ½( 3 ± √5)
5.5 ( 8 - x ) + 44 = 104 - 3.5 ( 3x + 24 )
Distribute 5.5 through the parenthesis.
44 - 5.5x + 44 = 104 - 10.5x - 84
Add the numbers.
88 - 5.5x = 20 - 10.5x
Move variable to the left side and change its sign.
88 - 5.5x + 10.5x = 20
-5.5x + 10.5x = 20 -88
Collect like terms.
5x = 20 - 88
Calculate the sum or difference.
5x = - 68
Divide both sides by 5.
x = - 68 / 5