All categories

3 years ago

How would you write 4.3756 in standard decimal form

Physics

1 answer:

VMariaS [17]3 years ago

4 0

It can be 5.64x10^-7
5.64x 10^8

You might be interested in

Which of the following sentences best explains the relationship between cellular respiration and glucose?

Papessa [141]

Hi, can you list the sentences ?

3 0

3 years ago

A 3 μf capacitor is connected to a 6 v battery. what is the charge on each plate of the capacitor?

Lapatulllka [165]

C = 3 uf = 3 × 10^(-6) f
v = 6volts
Q = C.v
= <span>3 × 10^(-6) </span>× 6
= 18 × 10^(-6)
= 1.8 = 10^(-5)

5 0

3 years ago

A capacitor is being charged from a battery and through a resistor of 10 kΩ. It is observed that the voltage on the capacitor ri

swat32

Answer:

$C = 2.48 \times 10^{-4} Farad$

Explanation:

As per the equation of voltage on capacitor we know that

$V = V_{max}(1 - e^{-\frac{t}{\tau}})$

now we know that voltage reached to its 80% of maximum value in 4 second time

so we will have

$0.80 V_{max} = V_{max}(1 - e^{-\frac{4}{\tau}})$

$0.20 = e^{-\frac{4}{\tau}}$

$-\frac{4}{\tau} = ln(0.20)$

$-\frac{4}{\tau} = -1.61$

$\tau = 2.48$

as we know that

$\tau = RC$

$(10 k ohm)(C) = 2.48$

$C = 2.48 \times 10^{-4} Farad$

4 0

3 years ago

When the pendulum bob reaches the mean position, the net force acting on it is zero. Why then does it swing past the mean positi

ryzh [129]

Answer:

<u>The pendulum bob swing past the mean position because:</u>

When a pendulum's bob is accelerating at its extreme position its velocity is zero. Due to the restoring toque the bob starts to accelerates towards its mean postion. The maximum acceleration of the pendulum's bob is $-w^{2} A$ and the the acceleration decreases as $-w^{2} x$ towards the mean position.

The acceleration at the mean position becomes zero but the velocity remains maximum. Hence the bob continues to move and does not stops.Thus it can summarised as the force decreases ,acceleration decreases and velocity increases at slow rate.

6 0

3 years ago

A 75 kg pilot flies a plane in a loop. At the top of the loop, where the plane is completely

erica [24]

Answer:

1.47 km

Explanation:

When the pilot hangs freely in the seat and does not push against the seat belt, his centripetal acceleration would counter balance gravitational acceleration g = 9.81m/s2 = a

We can calculate the radius of the loop using velocity v = 120m/s and a

$a = \frac{v^2}{r}$

$r = \frac{v^2}{a} = \frac{120^2}{9.81} = 1467.89 m$ or 1.46 km

6 0

4 years ago