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castortr0y [4]
3 years ago
12

A sled is moving at a constant speed down a surface inclined at 45.0 with the horizontal and travels 30 meters in 4 seconds calc

ulate the vertical velocity of the sled at the end of the 4 seconds

Physics
1 answer:
Alexxandr [17]3 years ago
3 0

Because the speed of the sled is constant throughout this ordeal, we know that the instantaneous and average velocities are equal, and the velocity of the sled is

v=\dfrac{-30\,\mathrm m}{4\,\mathrm s}=-7.5\,\dfrac{\mathrm m}{\mathrm s}

(negative because we're taking the downward direction to be negative)

The vertical component of this vector is given by

v_y=\|v\|\sin\theta

where \theta is the angle made by the velocity vector with the positive x-axis (taken to be the right direction). Here, \theta=225^\circ, so

v_y=\left(7.5\,\dfrac{\mathrm m}{\mathrm s}\right)\sin225^\circ\approx-5.3\,\dfrac{\mathrm m}{\mathrm s}

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