Nope, this is impossible because in order for a car to pass another, they the 55 mph car would have to be behind the 65 mph car (meaning that starting ahead of the 65 mph doesn't count as pass). Assuming that they both drive for one hour, it is impossible because the first will cover a distance of 65 mi and the second would cover a distance of 55 mi. One is obviously ahead of the other and is therefore impossible for the slow one to pass the first one unless the slow car keeps driving after an hour. In that case, it would take approximately 11 minutes for it to pass the other car. This was found by finding the distance needed to pass the first car : 65 - 55 = 10 mi and converted using 1 hr/ 55 mi = .18181818 hr x 60 min/ 1 hr = 11 seconds I hope this helps :)
Sure it is. We only know the average speeds, but we don't know how much of the time each car drove faster or slower.
The averages only tell us who got to the end of their trip sooner. But there could have been a time ... or several times during the hour ... when the 55mph car was blazing and passed the 65mph car.
In fact, the 55mph car could have been driving at 110 mph for the first 29 minutes, then the last 1.83 miles at a speed of 3.5 mph. His average would then be 55mph, even though he spent the first 29 minutes passing everybody and everything on the road in the first 53.16 miles of his trip.
