Question

Evaluate the integral. (Use C for the constant of integration.) cos(x) (8 + 7 sin^2(x)) dx

Answer 1

Answer: $8 \sin x +7(\dfrac{\sin^3x}{3})+C$

Step-by-step explanation:

Consider $\int \cos(x) (8+7 \sin^2(x)) \, dx$

Substitute  t= sinx

then dt = cos x dx

$\int \cos(x) (8+7 \sin^2(x)) \, dx = \int (8+7t^2)dt\\\\ =8t+7(\dfrac{t^3}{3})+C$

$[\int x^ndx=\dfrac{x^{n+1}}{n+1}+C]$

$=8 \sin x +7(\dfrac{\sin^3x}{3})+C$

Hence, $\int \cos(x) (8+7 \sin^2(x)) \, dx=8 \sin x +7(\dfrac{\sin^3x}{3})+C$