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Stels [109]
3 years ago
13

Evaluate the integral. (Use C for the constant of integration.) cos(x) (8 + 7 sin^2(x)) dx

Mathematics
1 answer:
UNO [17]3 years ago
5 0

Answer: 8 \sin x +7(\dfrac{\sin^3x}{3})+C

Step-by-step explanation:

Consider \int \cos(x) (8+7 \sin^2(x)) \, dx

Substitute  t= sinx

then dt = cos x dx

\int \cos(x) (8+7 \sin^2(x)) \, dx = \int (8+7t^2)dt\\\\ =8t+7(\dfrac{t^3}{3})+C

[\int x^ndx=\dfrac{x^{n+1}}{n+1}+C]

=8 \sin x +7(\dfrac{\sin^3x}{3})+C

Hence, \int \cos(x) (8+7 \sin^2(x)) \, dx=8 \sin x +7(\dfrac{\sin^3x}{3})+C

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