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3 years ago

When you solve a linear equation how do you recognize if the equation has 1 solution no

Mathematics

1 answer:

damaskus [11]3 years ago

4 0

Answer:

If you solve a linear equation you have two different lines.

Now with that being said the solutions are as follows;

One Solution: The slopes are different

No solution: The slopes are the same and the y intercepts are different

Infinite Solutions: The slopes are the same and the y intercepts are different

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A scale drawing for a rectangular parking lot is shown. Find the area of the scale drawing.

zhenek [66]

Answer:

113.52 sq cm

Step-by-step explanation:

13.2 times 8.6 is 113.52. You get area by multiplying a length and a width.

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2 years ago

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-1/2(2x-6)+9=-8 answer

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Answer:

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1⁄2 × 1⁄5 = help//.....

skad [1K]

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1/10

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1/2 * 1/5

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Which scatterplot does NOT suggest a linear relationship between and y

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C; this is because the line of beat fit isn’t linear but curved in that one graph.

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2 years ago

In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: Chapter Reference b The length of the

Butoxors [25]

Answer:

The length of the angle bisector of angle ∠A is 6.01.

Step-by-step explanation:

It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.

Using pythagoras theorem

$(AB)^2=(BC)^2+(AC)^2$

$(13)^2=(BC)^2+(5)^2$

$169=(BC)^2+25$

$BC=12$

$\sin A=\frac{\text{perpendicular}}{\text{hypotenuse}}$

$\sin A=\frac{BC}{AB}$

$A=\sin ^{-1}\frac{12}{13}$

$A=67.38$

Bisector divides the angle in two equal parts, therefore,

$A'=\frac{67.38}{2} =33.69$

In triangle ACD.

$\cos A'=\frac{\text{Base}}{\text{Hypotenuse}}$

$\cos A'=\frac{AC}{AD}$

$\cos (33.69^{\circ})=\frac{5}{AD}$

$0.832=\frac{5}{AD}$

$AD=\frac{5}{0.832} =6.009\approx 6.01$

Therefore the length of the angle bisector of angle ∠A is 6.01.

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2 years ago