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3 years ago

WILL MARK BRAINLIEST!! define the following career and miscellaneous terms:

Mathematics

1 answer:

Scorpion4ik [409]3 years ago

8 0

Answer: IM pretty sure your correct

Step-by-step explanation:

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Write the expressions as an equivalent power with a negative exponent. 1/49 and 27/125

hoa [83]

$n^{-x}=\frac1{n^x}$

$\textcircled1\ \frac1{49}=\frac1{7^2}=\boxed{7^{-2}}$

$\textcircled2\ \frac{27}{125}=\frac{3^3}{5^3}=(\frac35)^3=\frac1{(\frac{5}{3})^3}=\boxed{\left(\frac53\right)^{-3}}$

7 0

3 years ago

I can't find the answer

Rudik [331]

Answer: what grade is this

Step-by-step explanation:

3 0

3 years ago

Consider the equation x^2 = 36. Which of the statements below are true? Select all that apply.

Dmitry [639]

Answer:

x = 6 and x = -6

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

Sarah received a gift in a rectangular box with a volume of 240 in3. If the base of the box was 20 in2, how tall was the box? A)

sergiy2304 [10]

Answer:

<em>12 inches</em>

Step-by-step explanation:

volume = length * width * height

volume = (length * width) * height

volume = (area of base) * height

height = volume/(area of base)

height = (240 in^3)/(20 in^2) = 12 in

6 0

3 years ago

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Solve the simultaneous equations

Contact [7]

Answer:

The solution for given system of equations is: x = 6 and y = 3

(6,3)

Step-by-step explanation:

Given equations are:

$3x+4y=30\ \ \ Eqn\ 1\\3x-y=15\ \ \ \ Eqn\ 2$

There are three methods to solve simultaneous equations

Elimination
Substitution
Co-efficient method

We will use the elimination method as the coefficients of x in both equations are already same

Subtracting equation 2 from equation 1

$3x+4y - (3x-y) = 30-15\\3x+4y-3x+y = 15\\5y = 15\\\frac{5y}{5} = \frac{15}{5}\\y = 3$

Putting y = 3 in equation 2

$3x-3 = 15\\3x = 15+3\\3x = 18\\\frac{3x}{3} = \frac{18}{3}\\x = 6$

Hence,

The solution for given system of equations is: x = 6 and y = 3

(6,3)

7 0

3 years ago