The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>
The equation of the function is given as:

Expand the function

Reorder the terms

Factor the expression

Factor out x -1

Expand

Factorize
](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Bx%28x%20%2B%203%29%20%2B%202%28x%20%2B%203%29%5D%28x%20-%201%29)
Factor out x + 2

The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
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Answer:
27!!! I understand it!
Step-by-step explanation:
Monday: 1 , 2 (Anthony and his 2 friends)
They EACH invited two friends!
Tuesday: Anthony: 2 Friend 1: 2 Friend 2: 2
The same!!
Wednesday: A: 2 F1: 2 F2: 2
THE SAME AGAIN!
Thrusday: A: 2 F1: 2 F2: 2
THE SAME AGAIN!!
Friday: A: 2 F1: 2 F2: 2
1 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 = 27
Hope it helps!!
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Answer:
1000
7/100
Step-by-step explanation:
10×10×10is 100
Answer: i cant help you because it don't make sense
Step-by-step explanation: