Answer:
d. Variable ratio
Step-by-step explanation:
We are asked to determine that gambling at a slot machine is an example of which reinforcement schedule.
Let us see our given choices one by one.
a. Fixed ratio
We know that in fixed ratio schedule, reinforcement is delivered after the completion of a number of responses. An example of fixed ratio is a reward to every 6th response.
b. Fixed interval
We know that in fixed interval schedule the first response is rewarded only after a specified amount of time has elapsed. An example of fixed interval schedule is weekly paycheck.
c. Variable interval
We know that in variable interval schedule, the reinforcement is delivered at changing and unpredictable intervals of time.
d. Variable ratio
In variable ratio schedule, a response is reinforced after an unpredictable number of responses. Gambling and lottery are examples of variable ratio.
Therefore, option 'd' is the correct choice.
Answer:
the g's contributing term for the overall uncertainty of P is ![dP_g = [\frac{dg}{g}]](https://tex.z-dn.net/?f=dP_g%20%3D%20%20%5B%5Cfrac%7Bdg%7D%7Bg%7D%5D)
Step-by-step explanation:
From the question we are told that
The pressure is 
The first step in determining the uncertainty of P in by obtaining the terms in the equation contributing to it uncertainty and to do that we take the Ln of both sides of the equation

=>
Then the next step is to differentiate both sides of the equation

=> 
We asked to obtain the contribution of the term g to the uncertainty of P
This can deduced from the above equation as
![dP_g = [\frac{dg}{g}] P](https://tex.z-dn.net/?f=dP_g%20%3D%20%20%5B%5Cfrac%7Bdg%7D%7Bg%7D%5D%20P)
Answer:
if you multiply two negatives together, then the answer is positive, so -1/4 of -4 is just 4 / 4 which is 1