The rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
<h3>Howe to solve for the rate of the plane and wind</h3>
In 7 hours the kilometer traveled = 4340
P + W = 4340/7
= 620
P-W = 3120/3 hours
= 1040
2p = 1040 + 620
= 1660
p =830
W = 1040 - 830
= 210
Hence the rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
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Answer:
T depends on what y equals. -1/4y, i guess
Step-by-step explanation:
Answer:
a = 60°
Step-by-step explanation:
From the picture attached,
In the given triangle,
NE and ML are the perpendicular bisectors of two sides of the triangle.
Therefore, m∠MEK = m∠MLK = 90°
Since, sum of interior angles of polygon KLME = 360°
m∠MEK + m∠MLK + m∠EML + m∠EKL = 360°
90° + 90° + 120° + a = 360°
a = 360° - 300°
a = 60°
Answer:
B
Step-by-step explanation:
This kinda easy. Every 3 yellow drops is 4 blue drops, so here's the answer. 3 = 4, 6 = 8, 9 = 12, 12 = 16. so you would need 16 blue drops.
