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kaheart [24]
3 years ago
9

I just need help on this problem please. Thanks :)

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0
All of them are the correct answer.
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PLEASE HELP ME!!!!
Tasya [4]

Answer:

20/7

Step-by-step explanation:

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3 years ago
Which of these sequences of transformations would not return a shape to its original position?
nikdorinn [45]

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A

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5 0
3 years ago
Point O is the center of the given circle. What is the measure of YZ?
Rina8888 [55]
Let a chord join YZ, then angle XYZ = 90° and angle XZY = 90 - 54 = 36°
angle OYZ = angle XZY = 36°

Therefore, the measure of YZ = 180 - 36 - 36 = 108°

6 0
3 years ago
Read 2 more answers
Help on this one as well ii manged to get an answer but If you understand it or im wrong an you please explain ! thank you !!
AnnZ [28]
Almost got it!

x + 3 = 3(y + 2)/2 [Multiplied both sides by 3]
so x + 3 = (3y + 6)/2
2(x + 3) = 3y + 6 [Multiplied both sides by 2]
2x + 6 = 3y + 6
2x = 3y [Subtracted 6 from both sides]
x = 3y/2 [Divided both sides by 2]
x/3 = y/2 [Divided both sides by 3]

So you wrote y/3 instead of y/2 
Hope this helped!
8 0
3 years ago
Read 2 more answers
How do you do question b?
notsponge [240]

Part (b)

We use the result of part (a) and plug in (x,y) = (0,0). This is directly from the initial condition y(0) = 0.

\arcsin(4y) = x^2 + C\\\\\arcsin(4*0) = (0)^2 + C\\\\\arcsin(0) = C\\\\0 = C\\\\C = 0\\\\

-----------------

This means,

\arcsin(4y) = x^2 + C\\\\\arcsin(4y) = x^2 + 0\\\\\arcsin(4y) = x^2\\\\4y = \sin(x^2)\\\\y = \frac{1}{4}\sin(x^2)\\\\

is the solution with the initial condition y(0) = 0.

6 0
3 years ago
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