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kaheart [24]
3 years ago
9

I just need help on this problem please. Thanks :)

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0
All of them are the correct answer.
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x2y - 2xy - 24y = y(x2 - 2x - 24) What is the completely factored form of x2y – 2xy – 24y? (xy + 4)(x – 6) xy(x + 4)(x – 6) y(x
likoan [24]

we are given

x^2y-2xy-24y=y(x^2-2x-24)

now, we can factor out right side term

x^2-2x-24=x^2-6x+4x-6*4

x^2-2x-24=(x-6)(x+4)

now, we can plug back

and we get

so,

x^2y-2xy-24y=y(x-6)(x+4).............Answer

5 0
2 years ago
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a game room floor that is 120 feet by 75 feet. a scale drawing of the floor on grid paper uses a scale of 1 unit:5 feet. what ar
lubasha [3.4K]
24 feet by 15 feet

You divide each nukber by 5 bevause that is the given scale factor.
5 0
3 years ago
Is - 11>-16 a true pr false statement
Elina [12.6K]

Answer:

True

Step-by-step explanation:

-11 is greater than -16

6 0
3 years ago
Number 14 NEED HELP NOW pls
inessss [21]

Answer:

E

Step-by-step explanation:

5 0
3 years ago
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Scores on an exam follow an approximately bell shaped distribution with a mean of 76.4 and a standard deviation of 6.1 points. A
Crazy boy [7]

Answer:

b) 95%

Step-by-step explanation:

We have been given that scores on an approximately bell shaped distribution with a mean of 76.4 and a standard deviation of 6.1 points. We are asked to find the percentage of the data that is between 64.2 points and 88.6 points.

First of all, we will find z-scores of each data point as:

z=\frac{x-\mu}{\sigma}

z=\frac{64.2-76.4}{6.1}

z=\frac{-12.2}{6.1}

z=-2

Let us find z-score corresponding to normal score 88.6.

z=\frac{88.6-76.4}{6.1}

z=\frac{12.2}{6.1}

z=2

To find the percentage of the data is between 64.2 points and 88.6 points, we need to find area under a normal distribution curve that lie within two standard deviation of mean.

The empirical rule of normal distribution states that approximately 95% of data points fall within two standard deviation of mean, therefore, option 'b' is the correct choice.

6 0
3 years ago
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