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Flauer [41]
3 years ago
11

Express 7 min.30sec.as a percentage of 1 hour .​

Mathematics
2 answers:
const2013 [10]3 years ago
6 0

Time percentage

7 1

30 x

cross multiple

7(x) = 30(1)

7x=30

divide both side by 7

7cancell 7 living

x = <u>3</u><u>0</u>

7

x = <u>3</u><u>0</u>

7

cross multiple

fgiga [73]3 years ago
3 0

Answer:

well for me

Step-by-step explanation:

7 mins

7×60

=420

plus the 30sec

450 sec

450/3600×100

45000/3600

450/36

12.5

that's how I can help

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14x⁴+35x² factor out the GCF
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Step 1. Find the Greatest Common Factor (GCF)

GCF = 7x^2

Step 2. Factor out the GCF (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

7x^2(14x^4/7x^2 + 35x^2/7x^2)

Step 3. Simplify each term in parentheses

7x^2(2x^2 + 5)

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2 years ago
Int he figure below find AC
Ahat [919]

Given :-

  • Two triangles with their two angles equal .

To Find :-

  • Measure of AC .

Answer :-

Here in ∆ABC and ∆EDC ,

  • \angle CAB = \angleCED (given )
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Therefore by AA similarity criterion , we can say that ∆ABC ~ ∆EDC . Also we know that corresponding sides of similar triangles are proportional . So ,

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→ AC/9 = 8/12

→ AC = 8/12 * 9

→ AC = 6

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I hope this helps.

7 0
2 years ago
Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that th
11111nata11111 [884]

Answer:

The null hypothesis is H_0: \mu = 14

The alternate hypothesis is H_a: \mu < 14

The test statistic is t = -1.95.

The p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

Step-by-step explanation:

Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that their highlighters could write continuously for 14 hours.

At the null hypothesis, we test if the mean is 14 hours, that is:

H_0: \mu = 14

At the alternate hypothesis, we test if the mean is less than 14 hours, that is:

H_a: \mu < 14

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

14 is tested at the null hypothesis:

This means that \mu = 14

X = 13.6 hours, s = 1.3 hours. Sample of 40:

In addition to the values of X and s given, we have that n = 40

Test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{13.6 - 14}{\frac{1.3}{\sqrt{40}}}

t = -1.95

The test statistic is t = -1.95.

P-value:

The p-value of the test is the probability of finding a sample mean lower than 13.6, which is a left tailed test, with t = -1.95 and 40 - 1 = 39 degrees of freedom.

Using a calculator, the p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

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Answer:

Step-by-step explanation:

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3 years ago
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