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artcher [175]
3 years ago
15

Please help asap!!!!!! (picture)

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
6 0

Answer:6-\sqrt{21} , 6+\sqrt{21}

Step-by-step explanation:

For x^{2} =-12x+15, so x^{2} +12x-15=0 We apply the quadratic equation formula:(-b+-\sqrt{b^{2}-4*a*c })/2*a, where a=1, b=12 y c=-15. so;

(12+-\sqrt{12^{2} -4*1*(-15)} )/(2*1) = (12+-\sqrt{144-60})/2 = (12+-\sqrt{84})/2, but \sqrt{84} = 2\sqrt{21} We have that:

Solution : (6-\sqrt{21} , 6+\sqrt{21} )

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Again I need help, sorry but thank you!
musickatia [10]

Answer:

B)13 pints

Step-by-step explanation:

SO first we find the unit rate

We know that in 90 minutes (hour and a half), the water leaked 6 pints form 2;30 to 4

Now So we can divide to find unit rate

6/90=1/15

So 1 pint for every 15 minutes

And now we want to know the amount it takes from 2:30 to 6:30 which is 4 hours

40 hours is 240 minutes

SO we can divide now

240/15=16

SO 16 pints leaked but the question asked for remaining water in container

So 29-16 is 13

So B)13

3 0
3 years ago
Find the product (8/6n-4)(9n^2-4)
Leokris [45]

Answer:

4(3n+2) or 12n+8

Step-by-step explanation:

Given expression is:

(\frac{8}{6n-4})(9n^{2}-4)

The numerator of the fraction will be multiplied with 9n^2- 4

So, Multiplication will give us:

=\frac{8(9n^2-4)}{6n-4}

We can simplify the expression before multiplication.

The numerator will be broken down using the formula:

a^2 - b^2 = (a+b)(a-b)\\So,\\= \frac{8[(3n)^2 - (2)^2]}{6n-4}\\ = \frac{8(3n-2)(3n+2)}{6n-4}

We can take 2 as common factor from denominator

=\frac{8(3n-2)(3n+2)}{2(3n-2)}\\After\ cutting\\= 4(3n+2)

Hence the product is 4(3n+2) or 12n+8 ..

6 0
3 years ago
In one week, the 9th grade class recycled 9 2/3 pounds of glass and 12 3/4 pounds of newspaper. How many more pounds of newspape
mariarad [96]
15 4/5 because we are adding
7 0
3 years ago
I NEED HELP ASAP PLEASE!! I WILL AWARD BRAINLIEST
Irina-Kira [14]

9514 1404 393

Answer:

  • x ≥ 7
  • 54 -6m
  • y -x

Step-by-step explanation:

You have to realize that the absolute value function will change the sign of its argument only if that argument is negative.

108. |x -7| = x -7 . . . . . true for x-7≥0

  x ≥ 7 . . . . makes the statement true

__

1a. When m < 9, the value 6m is less than 54, so 6m-54 < 0. That means the absolute value function changes the sign of its argument:

  54 -6m . . . . . simplified form for m < 9

__

1b. |y -x| = y -x . . . when y > x, the argument of the absolute value is positive

6 0
3 years ago
Let g(x) = -x2 + x. Find g(-10).
Inessa05 [86]

Answer:

10

Step-by-step explanation:

6 0
3 years ago
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