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Ainat [17]
2 years ago
13

Translate the phrase into an algebraic expression, the product of 8 and y?

Mathematics
1 answer:
SVETLANKA909090 [29]2 years ago
4 0

Answer:

8y

Step-by-step explanation:

Product means multiply

8*y

8y

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Find the average rate of change of the function over the given interval.
Minchanka [31]

Answer:

Average rate of change = 20.2

Rate of change at the left endpoint :   f' (5) = 4t = 20

Rate of change at the right  endpoint : f' (5.1) = 4*5.1 = 20.4

Step-by-step explanation:

The average rate of change of the function

F(t) = 2t^2 - 1 ,  [ 5,5.1 ]

solution

\frac{f(5.1)-f(5)}{5.1 - 5} = \frac{2*(5.1)^2-1-(2*5^2-1)}{0.1}   = [ 2 ( 26.01 - 25 ) / 0.1 ]

= 2.02 / 0.1 = 20.2

Rate of change at the left endpoint :   f' (5) = 4t = 20

Rate of change at the right  endpoint : f' (5.1) = 4*5.1 = 20.4

6 0
3 years ago
Please help me with this will reward brainlest
larisa [96]

5.35 + 3.8 + 2 = 11.15 pounds in total

Answer

D. 11.15

6 0
3 years ago
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25 tests in all 23 Are perfect tests what percent are perfect
madreJ [45]
92% is the amount that are perfect
5 0
2 years ago
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SOMEONE PLZ HELP ME!!!!!!!!! I WILL LOVE YOU!!!!!!!!!!
Nookie1986 [14]
<h3><u>Answer: Middle Number</u></h3><h2>Your Explanation</h2>

The mean is the middle number of the numbers.

Example:

1 2 3 4 5 6 7

The middle number here is 4.

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5 0
3 years ago
If a point P(x,y) is the equidistant from the points A(2,3) and B(6,1), find the equation of locus of moving point P.​
jekas [21]

Answer:

y=2x-6

Step-by-step explanation:

A locus can be defined as a curve or figure formed by all the points satisfying a particular equation of the relation between coordinates.

The condition stated in the question is such that a generic (x,y) point of the curve is equidistant from the points A(2,3) and B(6,1).

The distance d1 from (x,y) to (2,3) is:

d_1=\sqrt{(x-2)^2+(y-3)^2}

The distance d2 from (x,y) to (6,1) is:

d_2=\sqrt{(x-6)^2+(y-1)^2}

Since d1=d2:

\sqrt{(x-2)^2+(y-3)^2}=\sqrt{(x-6)^2+(y-1)^2}

Squaring both sides:

(x-2)^2+(y-3)^2=(x-6)^2+(y-1)^2

Operating:

x^2-4x+4+y^2-6y+9=x^2-12x+36+y^2-2y+1

Simplifying all the squares:

-4x+4x+4-6y+9=-12x+36-2y+1

Moving the variables to the left side and the numbers to the right side:

-4x+12x-6y+2y=36+1-4-9

Simplifying:

8x-4y=24

Dividing by 4:

2x-y=6

Or, equivalently:

\boxed{y=2x-6}

7 0
3 years ago
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