No, there are not any outliers because all of the numbers are relatively close in value
Answer:
Probability of getting a number which is not 2 = 7/8
Step-by-step explanation:
Given;
Total number of faces = 8
Number of face with 2 = 1
Number of face with 3 = 2
Number of face with 4 = 1
Number of face with 7 = 3
Number of face with 9 = 1
Find:
Probability of getting a number which is not 2
Computation:
Probability of not an event = 1 - [Number of favourable outcomes / Total number of outcomes]
Probability of getting a number which is not 2 = 1 - [1/8]
Probability of getting a number which is not 2 = [8-1] / 8
Probability of getting a number which is not 2 = 7/8
Good morning
21 + 3q < 3(13 - q)
21+ 3q < 39 - 3q Here it was -3q and it was on the left side. However when you are switching it to another terms that looks like it you must change the sign as well.
3q + 3q < 39 - 21 Here I bring the common terms together.
6q < 18
Divide both sides by 6
6q/6 < 18/6
q < 3
If <em>c</em> > 0, then <em>f(x</em> - <em>c)</em> is a shift of <em>f(x)</em> by <em>c</em> units to the right, and <em>f(x</em> + <em>c)</em> is a shift by <em>c</em> units to the left.
If <em>d</em> > 0, then <em>f(x)</em> - <em>d</em> is a shift by <em>d</em> units downward, and <em>f(x)</em> + <em>d</em> is a shift by <em>d</em> units upward.
Let <em>g(x)</em> = <em>x</em>. Then <em>f(x)</em> = <em>g(x</em> + <em>a)</em> - <em>b</em> = (<em>x</em> + <em>a</em>) - <em>b</em>. So to get <em>g(x)</em>, we translate <em>f(x)</em> to the left by <em>a</em> units, and down by <em>b</em> units.
Note that we can also interpret the translation as
• a shift upward of <em>a</em> - <em>b</em> units, since
(<em>x</em> + <em>a</em>) - <em>b</em> = <em>x</em> + (<em>a</em> - <em>b</em>)
• a shift <em>b</em> units to the right and <em>a</em> units upward, since
(<em>x</em> + <em>a</em>) - <em>b</em> = <em>x</em> + (<em>a</em> - <em>b</em>) = <em>x</em> + (- <em>b</em> + <em>a</em>) = (<em>x</em> - <em>b</em>) + <em>a</em>.
