Which of the following statements about trapezoids is true?? (Help asap) !!!!!!

Jacob is a teacher. He made 75 cookies to give to his students on the first day of school. He gave 2 cookies to each student who

Lisa [10]

Answer:

See explanation

Step-by-step explanation:

Jacob has 75 cookies.

He gave 2 cookies to each student.

Complete the table:

$\begin{array}{cc}\text{Number of student arrived}&\text{Number of cookies left}\\1&75-2=73\\2&73-2=71\\3&71-2=69\\...&...\end{array}$

Let n be the number of students. After nth student arrived Jacob had left

$g(n)=75-2n$

cookies.

This is an arithmetic sequence with

$g_1=g(1)=73\\ \\d=-2$

Thus,

$g_{n}=g_{n-1}-2\\ \\g(n)=g(n-1)-2$

3 0

3 years ago

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Dara buys a small drink for $1.75. A large drink costs 1.6 times as much as a small drink. How much does a large drink cost?

77julia77 [94]

I believe its $6.95 but i did that in my head so i might be wrong

3 0

2 years ago

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Jane's favorite fruit punch consists of pear, pineapple, and plum juices in the ratio 5:2:3. C How many cups of pear juice shoul

Gala2k [10]

This question is incomplete

Complete Question

Jane’s favorite fruit punch consists of pear, pineapple, and plum juices in the ratio 5:2:3.

a) How much of each juice is needed to make 25 liters of this punch?

b) How much punch can she make if she has only 6 cups of plum juice?

c) How many cups of pear juice should she use to make the quantity of punch from part (b)?

Answer:

a)For pear =

12.5 liters

For Pineapple

= 5 liters

For plum

= 7.5 liters

b) 20 cups of punch

c) 10 cups of pear juice

Step-by-step explanation:

Jane’s favorite fruit punch consists of pear, pineapple, and plum juices in the ratio 5:2:3.

The total proportion is :

5 + 2 + 3 = 10

a) How much of each juice is needed to make 25 liters of this punch?

For pear =

5/10 × 25 = 12.5 liters

For Pineapple

= 2/10 × 25 = 5 liters

For plum

= 3/10 × 25 = 7.5 liters

b) How much punch can she make if she has only 6 cups of plum juice?

The ratio of plum juice is 3

6 cups / 3 = 2 cups per portion

Since 2 equals 2/3 of 3,

The quantity of pineapple juice = 2/3 of the plum juice

2/3 x 6 cups = 4 cups

Since 5 equals 5/3 of 3, the amount of pear juice amount 5/3 of the plum juuce

5/3 x 6 cups = 10 cups

So, the number of cups are

Pear juice = 10 cups

Pineapple juice = 4 cups

Plum juice 6 cups

Total=( 10 + 4 + 6) = 20 cups of punch

c) How many cups of pear juice should she use to make the quantity of punch from part (b)?

10 cups of pear juice can be used to make the quantity of punch in part b

7 0

2 years ago

2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

(c) $P(X > 980) = 0.00001\\\\$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

$E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950$

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$