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3 years ago

pls help !! I need help with these few math problems !! Ily :) PLS SIMET WITH A LINK OF A PEICE OF PAPER WITH THE WORK :)

Mathematics

2 answers:

Y_Kistochka [10]3 years ago

8 0

Answer:

32x

384

Step-by-step explanation:

half of 64 is how far misty went with one gallon which gives you the answer for both a and b

32 multiplied by 12 gives you 384

N76 [4]3 years ago

3 0

Answer:

a.) 32 miles per gallon

divide by two to get one gallon

b.) She can go 32 miles on one gallon

use the info from part a

c.) 384 miles

multiply 32 by 12 to get 12 gallons

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Please help asap, shehhrhd

Dovator [93]

Answer:

55°

Step-by-step explanation:

y+x=180°

25°+30°+x=180°

25°+30°=y

y=55°

*Exterior Angle Theorem*

Sorry for the lack of explanation. It's midnight, so I didn't have much time.

7 0

3 years ago

6. In the diagram, find the value of y that makes b parallel to c. A778 34)

Margarita [4]

The answer would be thirty four

8 0

3 years ago

Read 2 more answers

F (x)= 4(2) f Find a

gavmur [86]

Answer:

Step-by-step explanation:

−4x

FACTOR

−(2−

))(x

−(

+2))

6 0

3 years ago

90 POINTS WILL GIVE BRAINLIEST!

Mandarinka [93]

Answer: a.) The printing press bc .25×200+35=85 and .15×200+50=80. And 80<85.

b.) 150 programs are needed to make them the same.

.25x+35=.15x+50 is 150.

Subtract .15x from both sides

Subtract 35 from both sides

Divide both sides by.10

7 0

3 years ago

Please help, this chapter was on derivatives...

weqwewe [10]

(3) Differentiating both sides of

$2x^{3/2} + y^{3/2} = 29$

with respect to x gives

$3x^{1/2} + \dfrac32 y^{1/2} \dfrac{\mathrm dy}{\mathrm dx} = 0$

Solve for dy/dx :

$\dfrac32 y^{1/2} \dfrac{\mathrm dy}{\mathrm dx} = -3x^{1/2} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{-3x^{1/2}}{\frac32y^{1/2}} = \dfrac{-2x^{1/2}}{y^{1/2}} = -2\sqrt{\dfrac xy}$

Then the slope of the tangent line to the curve at (1, 9) is

$\dfrac{\mathrm dy}{\mathrm dx} = -2\sqrt{\dfrac19} = -\dfrac23$

The equation of the tangent line would then be

y - 9 = -2/3 (x - 1) ==> y = -2/3 x + 29/3

(4) The slope of the tangent line to

$y=\dfrac{ax+1}{x-2}$

at a point (x, y) on the curve is

$\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{a(x-2)-(ax+1)}{(x-2)^2} = -\dfrac{2a+1}{(x-2)^2}$

When x = -1, we have a slope of 2/3, so

-(2a + 1)/(-1 - 2)² = 2/3

Solve for a :

-(2a + 1)/9 = 2/3

2a + 1 = -18/3 = -6

2a = -7

a = -7/2

7 0

3 years ago