<span>So we want to know the new coordinates for the vertex A'(x,y) if we know that the vertex A is at A(-1,2) and vertex B is at B(1,5) and that the triangle ABC is translated 6 units up and 3 units left. So the method is simply to add units 6 to x and 3 to y of A to get A'. Going left means we need to go to negative x direction and going up means we need to go to positive y direction. So: A'(-1-3,2+6) and that is: A'(-4,8). </span>
Angle QPS is an inscribed angle. Arc QS is the intercepted arc of that angle. The rule is that the intercepted arc is twice its angle measure. P measures 20 degrees, so arc QS measures 40 degrees. It just so happens that angle QTS is ALSO an inscribed angle intercepting arc QS. So angle QTS measures the same as angle P, 20 degrees. That's a. For b., we already stated the rule and figured out that minor arc QS is 40 degrees. For c., major arc QTS is 360 (the measure around the outside of a circle...EVERY circle in the world) minus the minor arc of 40. So major arc QTS measures 360 - 40 which is 320 degrees. There you go!
Answer:
hmmmm
Step-by-step explanation:
Answer: 9.8 inches
Step-by-step explanation:
Since x = 2 inches
Rainfall in April = x inches = 2 inches
Rainfall in May = x + 1.3 = 2 + 1.3 = 3.3 inches
Rainfall in June = 2x + 0.5 = 2(2) + 0.5 = 4.5
Total rainfall = 2 + 3.3 + 4.5 = 9.8 inches
Answer:
y=3x-12
Step-by-step explanation:
y=mx+b
then plug in known variables to find b
then once you know b, plug it and m back in to find your equation
