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3 years ago

Find the measure of the exterior Angle1 (I’m a bit confused on how exterior angles work)

Mathematics

1 answer:

sergejj [24]3 years ago

7 0

Answer:

Step-by-step explanation:

I would do 40 + 30 = 70

180-70 = 110

110 is the last angle bc all angles add to 180 in a triangle

Then 180 - 110 = 70 for angle 1 because their supplementary

I don't know if you could just add the 2 inside angles but I would do it this way to be safe until I know for sure.

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Really need help pls

antiseptic1488 [7]

Answer:

∠1 = 45°

∠2 = 45°

∠3 = 45°

∠4 = 90°

BC = 12

AB = 12

DC = 12

EB = 8.5

DB = 17

EC = 8.5

3 0

3 years ago

‼️help please ASAP ‼️

4vir4ik [10]

By the Law of Sine,
$\frac{ \sin(77) }{89} = \frac{ \sin(46) }{x}$
Solve for x and get x = 65.7.

7 0

3 years ago

Suppose that a standardized biology exam has a mean score of 80% correct, with a standard deviation of 3. The school administrat

NemiM [27]

Answer:

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.

This means that $n = 65, \pi = 0.76$

99% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 - 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.6236$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 + 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.8964$

0.6236*100 = 62.36%

0.8964*100 = 89.64%

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

6 0

3 years ago

Small notebooks cost $3.50 and large notebooks cost $5.00. She needs to buy 31 notebooks, and she has $134 to spend. How many sm

Darina [25.2K]

Let's assume

number of small notebooks =x

number of large notebooks =y

we are given

total number of notebooks =31

so, we get

$x+y=31$

now, we can solve for y

$y=31-x$

we have

Small notebooks cost $3.50 and large notebooks cost $5.00

she has $134 to spend

so, we get

$3.50x+5y=134$

now, we can plug y

$3.50x+5(31-x)=134$

$3.50x+5*31-5x=134$

$-1.5x+155=134$

$-1.5x+155-155=134-155$

$x=14$

now, we can find y

$y=31-14$

$y=17$

so,

number of small notebooks is 14

number of large notebooks is 17.............Answer

6 0

3 years ago

Read 2 more answers

Audrey is buying a new car for $32,998 she plans to make a down payment of $4200 if she makes monthly payment of $225 for the ne

marta [7]

32,998 -4,200 = 28,798 Total Loan Amount

Monthly Loan Payments = 225 for months = 13,500.00 for five years

This amount doesn't equal the principal so the problem could be worded incorrectly.

5 0

3 years ago