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4 years ago

The sum of four consecutive integers os -18. what is the greatest of these integers?

1 answer:

5 0

Hello! The sum of four consecutive integers that equal -18 are -6, -5, -4, And -3. -3 is the greatest out of all of the integers and -6 is least out of all the integers. The further right on the number line, the greater it is. The further left on the number line, the lower it is.

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I confused on this question

Fynjy0 [20]

42 degrees. Comment down if you need the explanation why

6 0

3 years ago

Read 2 more answers

Find the value of x in the triangle.

Hatshy [7]

Answer:

Step-by-step explanation:

The sum of measures of angles in triangle is allways 180°

So:

x + 53° + 60° = 180° {subtract 113° from both sides}

x = 67°

3 0

3 years ago

Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}

miskamm [114]

Answer:

$-3+i\sqrt{3} , 1+\sqrt{3}$

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

$\alpha = x+iy\\\beta = x-iy$

since they are conjugates

$\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}$

$\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}$

Imaginary part of the above =0

i.e. $\sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1$

So the value of alpha = $-3+i\sqrt{3} , 1+\sqrt{3}$

3 0

3 years ago

If t= 14,what is the value of 3t?

Goryan [66]

42 bro it’s pretty simple just multiplication

7 0

3 years ago

PLEASE HELP ME, I HAVE BEEN WAITING FOR A DAAYY!! How old am i if 400 reduced by 3 times my age is 244?

Vlad1618 [11]

Answer:

52 years

Step-by-step explanation:

Let

Your age = x

3 times your age = 3 * x

= 3x

The equation can be written as:

400 - 3x = 244

400 - 244 = 3x

156 = 3x

Divide both sides by 3

x = 156/3

x = 52

Therefore,

Your age is 52 years

4 0

3 years ago