All categories

3 years ago

Exercise 2

Mathematics

1 answer:

Ne4ueva [31]3 years ago

7 0

Answer:

The correct answer is 96 miles!!

Step-by-step explanation:

Jaxon drove 96 miles

Sense Jaxon was driving at the constant rate of 48 miles per hour for two hours you would do the equation 48 x 2 = 96.

Hope this helps!!

You might be interested in

It is given that D is inversely proportional to v m

Darina [25.2K]

Answer:

Step-by-step explanation:

$D=\frac{k}{\sqrt{m}}\\\\64=\frac{k}{\sqrt{9}}\\\\64=\frac{k}{3}\\\\ 64*3=k\\\\k=192\\a)D=\frac{192}{\sqrt{4}}\\\\=\frac{192}{2}\\\\D=96\\\\b)32=\frac{192}{\sqrt{m}}\\\\ 32*\sqrt{m}=192\\\\\sqrt{m}=\frac{192}{32}=6\\\\m=36$

8 0

3 years ago

Write 3 to the ninth times 3 to the seventh

lana66690 [7]

Answer:

3^9 * 3^7

Step-by-step explanation:

I don't really know how to explain it lol

6 0

3 years ago

Read 2 more answers

Help me with a. b. c. I need help

hammer [34]

Answer:

a) Perimeter = 20.5 Inches

Area is 15 Sq Inches

b) Perimeter is 61.4 Cms

Area is 210 Sq cm

c) Perimeter is 22 yards

Area is 21 Sq Yards

Step-by-step explanation:

a) Perimeter = sum of all the sides

= 8+7.5+5

=20.5

Perimeter = 20.5 Inches

Area of Triangle = $\frac{1}{2} \times height \times Base$

Base = 7.5 In

Height = 4 In

$A = \frac{1}{2} \times 4 \times 7.5$

$A = 2 \times 7.5$

$A = 15$

Hence Area is 15 Sq Inches

b) Perimeter = Sum of all the sides

P=13+23+13.4+12

P=61.4

Perimeter is 61.4 Cms

Area of trapezium = $\frac{1}{2} \times height \times (sum \ of \ parallel \ sides)$

$A= \frac{1}{2} \times 12 \times (12+23)$

$A= 6 \times 25$

$A=210$

Area is 210 Sq cm

c) Perimeter = Sum of all the sides

P = 7+4+7+4 ( as Opposite sides are equal in a parallelogram

P = 22

Perimeter is 22 yards

Area of a parallelogram = $base \times height$

$A= 7 \times 3$

$A = 21$

Area is 21 Sq Yards

3 0

3 years ago

Write the fraction in simplest form <br><br> 64/88

oksano4ka [1.4K]

The simplified form of 64/88 is 8/11I believe

3 0

3 years ago

Read 2 more answers

The J.R. Ryland Computer Company is considering a plant expansion to enable the company to begin production of a new computer pr

Solnce55 [7]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

Medium-Scale Large-Scale

Expansion Profit Expansion Profit

x f(x) y f(y)

Low 50 0.2 0 0.2

Demand Medium 150 0.5 100 0.5

High 200 0.3 300 0.3

a. Compute the expected value for the profit associated with the two expansion alternatives.

Which decision is preferred for the objective of maximizing the expected profit?

Expected value for medium scale expansion profit :

Expected value (E) = Σ(X) * f(x)

Σ[(50 * 0.2) + (150 * 0.5) + (200 * 0.3)]

= 145

Expected value for Large scale expansion profit :

Expected value (E) = Σ(X) * f(x)

Σ[(0 * 0.2) + (100 * 0.5) + (300 * 0.3)]

= 140

Medium scale expansion profit is preferred as it has the highest expected value.

b. Compute the variance for the profit associated with the two expansion alternatives.

Which decision is preferred for the objective of minimizing the risk or uncertainty?

Variance (V) = Σ(X - E)² * f(x):

Variance for medium scale expansion profit :

V = [((50-145)^2 * 0.2) + ((150-145)^2 * 0.5) + ((200-145)^2 * 0.3) = 2725

Variance for Large scale expansion profit :

V = [((0-140)^2 * 0.2) + ((100-140)^2 * 0.5) + ((300-140)^2 * 0.3) = 12400

Smaller variance is required to minimize risk, Hence, choose the medium scale expansion profit.

3 0

3 years ago