What is the slope of the line shown on the graph?
2 answers:
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To solve this we are going to use the exponential function: 
where
is the final amount after 
years
is the initial amount
is the decay or grow rate rate in decimal form
is the time in years
Expression A
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate, we are going to use the formula: 
*100%
*100%
*100%
5%
We can conclude that expression A decays at a rate of 5% every three months.
Now, to find the initial value of the function, we are going to evaluate the function at
We can conclude that the initial value of expression A is 624.
Expression B
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
*100%
*100
*100%
*100%
12%
We can conclude that expression B grows at a rate of 12% every 4 months.
Just like before, to find the initial value of the expression, we are going to evaluate it at
The initial value of expression B is 725.
We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months.
- Expression A has an initial value of 624, while expression B has an initial value of 725.
where
Expression A
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate
We can conclude that expression A decays at a rate of 5% every three months.
Now, to find the initial value of the function, we are going to evaluate the function at
We can conclude that the initial value of expression A is 624.
Expression B
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
We can conclude that expression B grows at a rate of 12% every 4 months.
Just like before, to find the initial value of the expression, we are going to evaluate it at
The initial value of expression B is 725.
We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months.
- Expression A has an initial value of 624, while expression B has an initial value of 725.