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Montano1993 [528]
3 years ago
11

What is the slope of the line shown on the graph?

Mathematics
2 answers:
Archy [21]3 years ago
8 0

Step-by-step explanation:

n I'll help u on the next one cuz I'm a lil lost

aivan3 [116]3 years ago
3 0

Answer: x/2 or 0.5

Step-by-step explanation:

rise over run a/b

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Suppose an ant walks counterclockwise on the unit circle from the point to the endpoint of the radius that forms an angle of rad
serg [7]

Answer:

\frac{4\pi}{3}

Step-by-step explanation:

The original questions is suppose an ant walks counterclockwise on a unit circle from the point (1,0) to the endpoint of the radius that forms an angle of 240 degrees with the positive horizontal axis.

To find the distance ant walked we find the arc length of the sector with central angle 240 degree and radius =1 (unit circle)

arc length of a sector =\frac{centralangle}{360} \cdot 2\pi r

arc length of a sector =\frac{240}{360} \cdot 2\pi(1)

arc length of a sector =\frac{2}{3} \cdot 2\pi

\frac{4\pi}{3}

6 0
3 years ago
While playing a trivia game Adam answer eight questions correct in the first half and two questions correct in the second half i
ratelena [41]

Answer:

80 points

Step-by-step explanation:

First Half:                                    Second Half:                        Total Right Answers

8 questions right            +          2 questions right        =       10 questions right

10*8 points a piece = 80 points

3 0
3 years ago
-1(2x+3)-2(x-1) simplified
Archy [21]

Answer:djd

Step-by-step explanation:weljfnw

6 0
3 years ago
Solve<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%20%5Ctimes%202%282%20%5Ctimes%204%29%7D%7B8%7D%20" id="TexFormula1" ti
creativ13 [48]
The answer is three you have to times the top numbers and divide
8 0
2 years ago
Read 2 more answers
Two forces with magnitudes of 90 and 50 pounds act on an object at angles of 30° and 160°, respectively. Find the direction and
Stels [109]
Force 1, F1 = 90, angle 30°

Force 2, F2 = 50, angle 160°

F1 = 90 cos(30) i + 90 sin (30) j
F2 = 50 cos (160) i + 50 sin (160) j

F1 = 90*0.866 i + 90*0.5 j
F2 = 50*(- 0.940) i + 50*0.342 j

F1 = 77.94 i + 45 j
F2 = -47 i +17.10 j

Resultant force, Fr = F1 + F2

Fr = [77.94 - 47.00] i +[45 +17.10]j = 30.94 i + 62.10 j

Magnitude = √[30.94 ^2 + 62.10^2] = 69.38 pounds

Direction  = arctan[62.10/30.94] = 63.52 °


7 0
3 years ago
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